Python - 法语年份/数字发音器

Question

我想尝试用我所学的东西制作一些东西，然后想到制作一个法语年份/数字发音器(基于文本)。我偶然发现了一些问题，比如如果我有不同的数字，它们都会交换位置等。我现在提供的代码仅适用于 4 位数字，如您所见，但我稍后会添加其他数字。我来这里问的是，如果我输入 ex，为什么脚本输出“deux”而不是“douze”。 1992、1982、1972 等？您会在代码末尾找到它。

由于不幸的是我没有设法正确格式化代码，所以我将不得不使用 pastebin:但首先我警告你；这可能会导致您的眼睛疼痛。我还没有理解 if/elif 等之间的区别。 http://pastebin.com/ZVU2N9m6

year = raw_input("Year: ")

a = "Mille"
b = ""
c = "cent"
d = ""
e = ""

if len(year) == 4: 

    # Decides century
    if year[1] == "9":
        b = " neuf "
    if year[1] == "8":
        b = " huit "
    if year[1] == "7":
        b = " sept "
    if year[1] == "6":
        b = " six "
    if year[1] == "5":
        b = " cinq "
    if year[1] == "4":
        b = " quatre "
    if year[1] == "3":
        b = " trois "
    if year[1] == "2":
        b = " deux "
    if year[1] == "1":
        b = " un "
    if year[1] == "0":
        c = ""

    # Sets decade
    if year[2] == "9":
        d = " quatre-vingt"
    if year[2] == "8":
        d = " quatre-vingt"
    if year[2] == "7":
        d = " soixante"
    if year[2] == "6":
        d = " soixante"
    if year[2] == "5":
        d = " cinquante"
    if year[2] == "4":
        d = " quarante"
    if year[2] == "3":
        d = " trente"
    if year[2] == "2":
        d = " vingt"

    # Sets year 
    if year[3] == "9":
        e = " neuf"
    if year[3] == "8":
        e = " huit"
    if year[3] == "7":
        e = " sept"
    if year[3] == "6":
        e = " six"
    if year[3] == "5":
        e = " cinq"
    if year[3] == "4":
        e = " quatre"
    if year[3] == "3":
        e = " trois"
    if year[3] == "2":
        e = " deux"
    if year[3] == "1":
        e = " et un"
    if year[3] == "0":
        e = ""

    # Sets year for 70s, 80s, 90s (different rule)
    elif year[2] == ("7", "8", "9") and year[3] == "2":
        e = "douze"

    print a + b + c + d + e

else:
    print "Your desired year does not have 4 digits"

Answer 1

因为 e = "douze" 永远不会到达。

 elif year[2] == ("7", "8", "9") and year[3] == "2":
     e = "douze"

我认为您在 ("7", "8", "9") 中输入了 year[2]。对于“82”，它确实应该是“deux”而不是“douce”。

---

实际上，列表或听写可以让您的生活更轻松。下面的代码片段生成从 1 到 99 的法语数字名称(不包括“et”，因为我不知道什么时候放):

def twoDigits (i):
    if not 0 < i < 100: raise Exception ('Out of bounds')
    below20 = [None, 'un', 'deux', 'trois', 'quatre', 'cinq', 'six', 'sept', 'huit', 'nuef',
        'dix', 'onze', 'douze', 'treize', 'quatorze', 'quinze', 'seize', 'dix-sept', 'dix-huit', 'dix-neuf']
    tens = [None, None, 'vingt', 'trente', 'quarante', 'cinquante', 'soixante', 'soixante', 'quatre-vingt', 'quatre-vingt']
    a, b = i // 10, i % 10
    if a in (1, 7, 9): b += 10
    return ' '.join (x for x in (tens [a], below20 [b] ) if x)

for a in range (1, 100):
    print (a, twoDigits (a) )