python - 为成对的名称分配相同的 ID

Question

nameList = ["sam", "tom", "jack", "james" , "robbie", "Lewis"]
id = 1

有一个nameList和一个初始化为1的id。

我想为列表中的前 2 个名称分配名称 ID，然后递增该 ID。

到目前为止我的代码片段:

nameList = ["sam", "tom", "jack", "james" , "robbie", "Lewis"]
id = 1
for names in nameList:
    print names + "," + str(id)
    id = id + 1

期望的输出是:-

sam,1
tom,1
jack,2
james,2
robbie,3
Lewis,3

有什么帮助吗？谢谢

Answer 1

您可以尝试使用 enumerate并检查字符串的索引是否偶数。如果是，增加id:

nameList = ["sam", "tom", "jack", "james" , "robbie", "Lewis"]
id = 0
for i, names in enumerate(nameList):
    if i % 2 == 0:   # if 'i' is even
        id = id + 1   # or id += 1, both are equivalent
    print names + "," + str(id) # if all elements are strings, 'str()' is not required

请注意，在每次迭代中，i 将采用 [0, length-1]

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