python - 如何使用 WSGI 实现 Flask 应用按路径调度？

Question

我想使用一个域作为多个 flask 应用程序的暂存环境，这些应用程序最终将在它们自己的域上运行。

类似于:

• example_staging.com/app1
• example_staging.com/app2
• example_staging.com/app3

哪里:

• example_staging.com/app1 与 app1.example_staging.com 相同
• example_staging.com/app2 与 app2.example_staging.com 相同
• example_staging.com/app3 与 app3.example_staging.com 相同

或:

• example_staging.com/app1 与 app1.com 相同
• example_staging.com/app2 与 app2.com 相同
• example_staging.com/app3 与 app3.com 相同

入门应用:

from flask import Flask

app = Flask(__name__)

@app.route('/')
def hello_world():
    return 'Hello from Flask!'

WSGI 入门配置文件:

import sys

project_home = u'/home/path/sample1'

if project_home not in sys.path:
    sys.path = [project_home] + sys.path

from app import app as application

引用:

http://flask.pocoo.org/docs/0.10/patterns/appdispatch/

我不知道在哪里添加文档中给出的示例代码以及 create_app、default_app、get_user_for_prefix 应该是什么样子。

注意:使用 PythonAnywhere

解决方案

Glenns 输入后的 WSGI 配置文件:

import sys

# add your project directory to the sys.path
project_home = u'/home/path/app1'
if project_home not in sys.path:
    sys.path = [project_home] + sys.path

from werkzeug.wsgi import DispatcherMiddleware
from app import app as app1
from app2.app import app as app2
from app3.app import app as app3

application = DispatcherMiddleware(app1, {
    '/app2':    app2,
    '/app3':    app3
})

文件夹结构:

app1 folder
    app2 folder
    app3 folder

Answer 1

这对我有用:

文件夹结构

DISPATCHER (folder)
   dispatcher.py

   app1 (folder)
       __init__.py

   app2 (folder)
       __init__.py

   app3 (folder)
       __init__.py

dispatcher.py

from flask import Flask
from werkzeug.wsgi import DispatcherMiddleware #use the commented version below for Werkzeug >= v.1.0
#from werkzeug.middleware.dispatcher import DispatcherMiddleware
from werkzeug.exceptions import NotFound

from app1 import app as app1
from app2 import app as app2
from app3 import app as app3

app = Flask(__name__)

app.wsgi_app = DispatcherMiddleware(NotFound(), {
    "/app1": app1,
    '/app2': app2,
    '/app3': app3
})

if __name__ == "__main__":
    app.run()

app1 到 app3 init.py

from flask import Flask

app = Flask(__name__)

@app.route("/")
def index_one():
    return "Hi im 1 or 2 or 3"

if __name__ == "__main__":
    app.run()

工作

python dispatcher.py

localhost:5000/app1 "Hi im one"
localhost:5000/app2 "Hi im two"
localhost:5000/app3 "Hi im three"

另一种配置

您可以导入另一个应用程序，例如 app0 并向应用程序添加菜单，使用 NotFound() 更改此设置

这有帮助

Application Dispatching