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python - 使用时出错 include ('admin.site.urls' ) : Passing a 3-tuple to include() is not supported

转载 作者:太空宇宙 更新时间:2023-11-03 13:30:17 25 4
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我是 Python 的新手,我正在使用 Lynda 上的视频教程来帮助我构建社交 Web 应用程序的框架。我正在尝试使用 cmd 中的 python manage.py runserver 从 cmd 运行服务器,但是,我一直遇到此错误消息。

CMD 提示错误

Traceback (most recent call last):

File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\utils\autoreload.py", line 225, in wrapper
fn(*args, **kwargs)
File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\core\management\commands\runserver.py", line 121, in inner_run
self.check(display_num_errors=True)
File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\core\management\base.py", line 364, in check
include_deployment_checks=include_deployment_checks,
File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\core\management\base.py", line 351, in _run_checks
return checks.run_checks(**kwargs)
File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\core\checks\registry.py", line 73, in run_checks
new_errors = check(app_configs=app_configs)
File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\core\checks\urls.py", line 40, in check_url_namespaces_unique
all_namespaces = _load_all_namespaces(resolver)
File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\core\checks\urls.py", line 57, in _load_all_namespaces
url_patterns = getattr(resolver, 'url_patterns', [])
File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\utils\functional.py", line 36, in __get__
res = instance.__dict__[self.name] = self.func(instance)
File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\urls\resolvers.py", line 536, in url_patterns
patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)
File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\utils\functional.py", line 36, in __get__
res = instance.__dict__[self.name] = self.func(instance)
File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\urls\resolvers.py", line 529, in urlconf_module
return import_module(self.urlconf_name)
File "C:\Users\Kelechi\AppData\Local\Programs\Python\Python35\lib\importlib\__init__.py", line 126, in import_module
return _bootstrap._gcd_import(name[level:], package, level)
File "<frozen importlib._bootstrap>", line 986, in _gcd_import
File "<frozen importlib._bootstrap>", line 969, in _find_and_load
File "<frozen importlib._bootstrap>", line 958, in _find_and_load_unlocked
File "<frozen importlib._bootstrap>", line 673, in _load_unlocked
File "<frozen importlib._bootstrap_external>", line 665, in exec_module
File "<frozen importlib._bootstrap>", line 222, in _call_with_frames_removed
File "C:\Windows\SysWOW64\bookmarks\bookmarks\urls.py", line 20, in <module>
url(r'^admin/', include(admin.site.urls)),
File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\urls\conf.py", line 27, in include
'provide the namespace argument to include() instead.' % len(arg)
django.core.exceptions.ImproperlyConfigured: Passing a 3-tuple to include() is not supported. Pass a 2-tuple containing the list of patterns and app_name, and provide the namespace argument to include() instead.

我的 urls.py 看起来像这样:

from django.contrib import admin

urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
...
]

最佳答案

在 Django 2.0 中,您不能再使用 include(admin.site.urls) ( release notes )。只需使用 admin.site.urls 即可。

from django.contrib import admin

urlpatterns = [
url(r'^admin/', admin.site.urls),
...
]

关于python - 使用时出错 include ('admin.site.urls' ) : Passing a 3-tuple to include() is not supported,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48203313/

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