python - 用python逐句拆分列表

Question

我有一个句子列表:

['hello', 'I would like to thank you', 'I would like to thank you. By the way']

当我找到“.”时，我需要将每个句子拆分成列表。 .

例如，在上面的例子中，期望的结果是:

['hello', 'I would like to thank you', 'I would like to thank you'. 'By the way']

我在 python 中尝试使用这段代码:

def split_pint(result):
    for i in result:
        i = re.split(r". ", i)
    return result

但是句子没有拆分。

有什么想法吗？

谢谢

Answer 1

使用简单的迭代和str.split

例如:

data = ['hello', 'I would like to thank you', 'I would like to thank you. By the way']

def split_pint(data):
    result = []
    for elem in data:
        result.extend(elem.split(". "))        
    return result

print(split_pint(data))

输出:

['hello', 'I would like to thank you', 'I would like to thank you', 'By the way']