python - SimpleJson 处理相同的命名实体

Question

我在 App Engine 中使用 Alchemy API，因此我使用 simplejson 库来解析响应。问题是响应中的条目具有 sme 名称

 {
    "status": "OK",
    "usage": "By accessing AlchemyAPI or using information generated by AlchemyAPI, you are agreeing to be bound by the AlchemyAPI Terms of Use: http://www.alchemyapi.com/company/terms.html",
    "url": "",
    "language": "english",
    "entities": [
        {
            "type": "Person",
            "relevance": "0.33",
            "count": "1",
            "text": "Michael Jordan",
            "disambiguated": {
                "name": "Michael Jordan",
                "subType": "Athlete",
                "subType": "AwardWinner",
                "subType": "BasketballPlayer",
                "subType": "HallOfFameInductee",
                "subType": "OlympicAthlete",
                "subType": "SportsLeagueAwardWinner",
                "subType": "FilmActor",
                "subType": "TVActor",
                "dbpedia": "http://dbpedia.org/resource/Michael_Jordan",
                "freebase": "http://rdf.freebase.com/ns/guid.9202a8c04000641f8000000000029161",
                "umbel": "http://umbel.org/umbel/ne/wikipedia/Michael_Jordan",
                "opencyc": "http://sw.opencyc.org/concept/Mx4rvViVq5wpEbGdrcN5Y29ycA",
                "yago": "http://mpii.de/yago/resource/Michael_Jordan"
            }
        }
    ]
}

所以问题是重复了“subType”，所以加载返回的字典只是“TVActor”而不是列表。有什么办法可以解决这个问题吗？

Answer 1

rfc 4627定义 application/json 说:

An object is an unordered collection of zero or more name/value pairs

和:

The names within an object SHOULD be unique.

这意味着 AlchemyAPI 不应在同一对象内返回多个 “subType” 名称并声称它是 JSON。

您可以尝试请求相同的 XML 格式 (outputMode=xml) 以避免结果中的歧义或将重复的键值转换为列表:

import simplejson as json
from collections import defaultdict

def multidict(ordered_pairs):
    """Convert duplicate keys values to lists."""
    # read all values into lists
    d = defaultdict(list)
    for k, v in ordered_pairs:
        d[k].append(v)

    # unpack lists that have only 1 item
    for k, v in d.items():
        if len(v) == 1:
            d[k] = v[0]
    return dict(d)

print json.JSONDecoder(object_pairs_hook=multidict).decode(text)

例子

text = """{
  "type": "Person",
  "subType": "Athlete",
  "subType": "AwardWinner"
}"""

输出

{u'subType': [u'Athlete', u'AwardWinner'], u'type': u'Person'}