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Android 自定义 Arrayadapter 不在 ListView 中显示数据

转载 作者:太空宇宙 更新时间:2023-11-03 13:17:06 26 4
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我想要一个有高分的页面。我为布局制作了一个 row.xml,并制作了一个自定义 ArrayAdapter。当我打印出我的对象时,我得到了正确的信息,但它没有出现在我的 ListView 中。它什么也没显示。

这是我的 row.xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="horizontal" >


<TextView
android:layout_width="0dp"
android:layout_height="wrap_content"
android:id="@+id/txtNumber"
android:layout_weight="1"
android:layout_gravity="center_horizontal"
android:text="@string/txtNumber" />

<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/txtName"
android:id="@+id/txtName"
android:layout_gravity="top|bottom"
android:layout_weight="1" />

<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/txtScore"
android:id="@+id/txtScore"
android:layout_weight="1" />


</LinearLayout>

我的自定义数组适配器

Package be.ehb.dt.multiscreen_highscores;
import android.content.Context;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.ArrayAdapter;
import android.widget.TextView;

import java.util.ArrayList;

// ** * Created by Naomi on 17/12/15. */

public class PersonAdapter extends ArrayAdapter<Person> {

public PersonAdapter(Context context, ArrayList<Person> personen) {
super(context,0, personen);
}

public View getView(int position, View convertView, ViewGroup parent) {
Person person = getItem(position);
if (convertView == null) {
convertView = LayoutInflater.from(getContext()).inflate(R.layout.row, parent, false);
}

TextView txtNumber = (TextView) convertView.findViewById(R.id.txtNumber);
TextView txtName = (TextView) convertView.findViewById(R.id.txtName);
TextView txtScore = (TextView) convertView.findViewById(R.id.txtScore);

txtNumber.setText(""+person.number);
txtName.setText(person.name);
txtScore.setText(""+person.score);
return convertView;
}
}

还有我的mainActivity

package be.ehb.dt.multiscreen_highscores;


import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;

import android.util.Log;
import android.widget.ListView;
import java.util.ArrayList;

public class MainActivity extends AppCompatActivity{
private ArrayList<Person> personen;

@Override
protected void onCreate(Bundle savedInstanceState){
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);

ArrayList<Person> arrayOfPersons = new ArrayList<Person>();
PersonAdapter adapter = new PersonAdapter(this,arrayOfPersons);
ListView v = (ListView) findViewById(R.id.listHighscores);


personen=new ArrayList<>();
personen.add(new Person(1,"Naomi",3454));
personen.add(new Person(2,"Steven",2394));
personen.add(new Person(3, "Lieven", 2254));
Log.d("print",personen.get(1).toString());
v.setAdapter(adapter);

}

}

最佳答案

你应该像这样修改你的适配器代码,

ArrayList<Person> personen;
public class PersonAdapter extends ArrayAdapter<Person> {

public PersonAdapter(Context context, ArrayList<Person> personen) {
super(context,0, personen);
this.personen = personen;

}

@Override
public int getCount() {
return personen.size();
}

现在到这里 Person person = personen.get(position);

编辑:

    ListView v = (ListView) findViewById(R.id.listHighscores);
personen=new ArrayList<>();
personen.add(new Person(1,"Naomi",3454));
personen.add(new Person(2,"Steven",2394));
personen.add(new Person(3, "Lieven", 2254));
Log.d("print",personen.get(1).toString());
PersonAdapter adapter = new PersonAdapter(this,personen)
v.setAdapter(adapter);

关于Android 自定义 Arrayadapter 不在 ListView 中显示数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34335472/

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