gpt4 book ai didi

c# - Ninject 的装饰器模式

转载 作者:太空宇宙 更新时间:2023-11-03 13:10:02 25 4
gpt4 key购买 nike

我正在尝试申请 this制作验证包装器的方法。我创建了以下接口(interface),我使用 Ninject 作为我的 DI 容器

public interface ICommandHandler<TCommand>
{
void Handle(TCommand command);
}

public interface IValidator<T>
{
IEnumerable<ValidationResult> Validate(T command);
}

public class ValidationCommandHandlerDecorator<T>:ICommandHandler<T>
{
private readonly ICommandHandler<T> _decoratee;
private readonly IValidator<T> _validator;

public ValidationCommandHandlerDecorator(ICommandHandler<T> decoratee,IValidator<T> validator )
{
_decoratee = decoratee;
_validator = validator;
}
public void Handle(T command)
{
this._validator.Validate(command);
this._decoratee.Handle(command);
}
}

public class SaveNewOsiRequestController : ApiController
{
private readonly ICommandHandler<OsiRequest> _osiRequestSaveHandler;

public SaveNewOsiRequestController(ICommandHandler<OsiRequest> osiRequestSaveHandler)
{
_osiRequestSaveHandler = osiRequestSaveHandler;
}
}

下面是我将具体类注入(inject) Controller 的方式:

        kernel.Bind(typeof (IValidator<>)).To(typeof (OsiRequestValidator));

kernel.Bind(typeof (ICommandHandler<>))
.To(typeof (SaveOsiRequestCommandHandler))
.WhenInjectedInto(typeof (ValidationCommandHandlerDecorator<>));

kernel.Bind(typeof (ICommandHandler<>))
.To(typeof (ValidationCommandHandlerDecorator<>))
.WhenInjectedInto(typeof(SaveNewOsiRequestController));

代码运行良好,没有任何问题。然而问题是我怎样才能用 Ninject 为另一个 Controller 做同样的注入(inject)?为了简单起见,我想像这样将另一个 Validator 和另一个 CommandHandler 注入(inject)到另一个 Controller 中:

        kernel.Bind(typeof (IValidator<>)).To(typeof (ANOTHER_Validator));

kernel.Bind(typeof (ICommandHandler<>))
.To(typeof (ANOTHER_CommandHandler))
.WhenInjectedInto(typeof (ValidationCommandHandlerDecorator<>));

kernel.Bind(typeof (ICommandHandler<>))
.To(typeof (ValidationCommandHandlerDecorator<>))
.WhenInjectedInto(typeof(ANOTHER_RequestController));

最佳答案

这里的问题是您正在执行通用绑定(bind),但您是在特定情况下使用它。只有当您希望泛型绑定(bind)适用于该绑定(bind)的所有情况(或至少是您可以有条件地绑定(bind)到的所有情况)时,您才想使用泛型绑定(bind)。

为此,您可以轻松地做到这一点:

kernel.Bind<IValidator<OsiRequest>>().To<OsiRequestValidator>();

kernel.Bind<ICommandHandler<OsiRequest>()
.To<SaveOsiRequestCommandHandler>()
.WhenInjectedInto<ValidationCommandHandlerDecorator<OsiRequest>>();

kernel.Bind<ICommandHandler<OsiRequest>()
.To<ValidationCommandHandlerDecorator<OsiRequest>()
.WhenInjectedInto<SaveNewOsiRequestController>();

那么每增加一个就是:

kernel.Bind<IValidator<DifferentRequest>>().To<DifferentValidator>();

kernel.Bind<ICommandHandler<DifferentRequest>()
.To<DifferentRequestCommandHandler>()
.WhenInjectedInto<ValidationCommandHandlerDecorator<DifferentRequest>>();

kernel.Bind<ICommandHandler<DifferentRequest>()
.To<ValidationCommandHandlerDecorator<DifferentRequest>()
.WhenInjectedInto<DifferentRequestController>();

您可以更改最后一个绑定(bind),这样您就不必为每种类型声明它:

kernel.Bind(typeof (ICommandHandler<>))
.To(typeof (ValidationCommandHandlerDecorator<>))
.WhenInjectedInto<ApiController>();

关于c# - Ninject 的装饰器模式,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29322248/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com