android - Android 中的简单 XML 解析

Question

我的xml如下所示:

<.sUID>yPkmfG3caT6cxexj5oWy34WiUUjj8WliWit45IzFVSOt6gymAOUA==<./sUID>
<.Shipping>0.00<./Shipping>
<.DocType>SO<./DocType>

我如何在 Android 中解析这个简单的 xml？

Answer 1

制作文档:

public Document XMLfromString(String v){

        Document doc = null;

        DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
        try {

            DocumentBuilder db = dbf.newDocumentBuilder();

            InputSource is = new InputSource();
            is.setCharacterStream(new StringReader(v));
            doc = db.parse(is); 

        } catch (ParserConfigurationException e) {
            e.printStackTrace();
        } catch (SAXException e) {
            System.out.println("Wrong XML file structure: " + e.getMessage());
            return null;
        } catch (IOException e) {
            e.printStackTrace();
        }

        return doc;

    }

然后这样读:

Document doc = x.XMLfromString("<XML><sUID>yPkmfG3caT6cxexj5oWy34WiUUjj8WliWit45IzFVSOt6gymAOUA==</sUID> <Shipping>0.00</Shipping> <DocType>SO</DocType></XML>");

NodeList nodes = doc.getElementsByTagName("XML");