c# - 意外的 token > jquery ajax

Question

我正在对 Web 方法进行 ajax 调用，但收到错误“意外 token >”我不确定为什么会收到此消息。有什么想法吗？

function addToQueue(me) {

    if (validateTimeFrame()) {
        $.ajax({
            method: "POST",
            url: "GenerateReportModal.aspx/AddToPrintQueue?id=" + $('#patientNum').val(),
            data: {buttonID: me.id},
            dataType: "json",
            success: function (data, textStatus, jqXHR) {
                alert(data);
                $('#GenerateReportModal').dialog('close');
            },
            error: function (jqXHR, textStatus, errorThrown) {
                console.log(errorThrown + ' ' + textStatus);
                console.log(jqXHR);
                $('#GenerateReportModal').dialog('close');
            }
        });
    }
}

<-------------------------------------------- ->

[WebMethod]
public string AddToPrintQueue(string buttonID)
{
    try
    {
        var deIdentify = 0;
        var adminUserNum = Int32.Parse(Session["AdminUserNum"].ToString());

        if ((Session["AdminUserNum"].ToString() == "6460" || Session["AdminUserNum"].ToString() == "6537" || Session["AdminUserNum"].ToString() == "7885") && (Session["ClinicalDataAdmin"].ToString() == "1" || Session["AccountAdmin"].ToString() == "1" || Session["SystemAdmin"].ToString() == "1"))
            deIdentify = (cbDeIdentify.Checked == true) ? 1 : 0;
        else
            deIdentify = 0;

        switch (buttonID)
        {
            case "FollowUpAddtoQueue":
                FollowUpAddToQueueClass(deIdentify);
                break;
            case "WearTimeAddToQueue":
                WearTimeAddToQueueClass(deIdentify);
                break;
            case "TrendsAddToQueue":
                TrendsAddToQueueClass(deIdentify);
                break;
            case "EndOfUseAddToQueue":
                EndofUseAddToQueueClass(deIdentify);
                break;
        }
     }
     catch
     {
        return "There was an issue, we appologize for the inconvenience";
     }

     return "Added to print queue";
 } 

<-------------------------------------------- ------>

<asp:Button runat="server" OnClientClick="return addToQueue(this); return false;" CssClass="button" ID="EndOfUseAddToQueue" Width="150" Text="<%$ Resources:PatientDetail, btnModAddtoQueue %>" />

Answer 1

您正在从您的 Web 方法返回一个字符串，但您已经告诉 jQuery 期待 JSON。

$.ajax({
    //...
    dataType: "json",
    //...
});

将其更改为文本(或将其完全删除)，看看是否能解决您的问题。请参阅 jQuery AJAX documentation 的 dataType 属性.