python - 类型错误 : 'NoneType' object is not callable, BeautifulSoup

Question

我遇到了一个奇怪的错误。我正在尝试做一些基本的解析。本质上，我正在以“x”格式收集数据，并希望以我可以使用的格式返回所有内容。我的直接问题是我的代码返回了一个奇怪的错误。我已经查看了此处针对同一问题的其他一些帖子/答案，但断章取意……确实很难查明问题所在。

data = url.text

soup = BeautifulSoup(data, "html5lib")

results = [] # this is what my result set will end up as

def parseDiv(text):
    #function takes one input parameter - a single div for which it will parse for specific items, and return it all as a dictionary
    soup2 = BeautifulSoup(text)
    title = soup2.find("a", "yschttl spt")
    print title.text
    print

    return title.text

for result in soup.find_all("div", "res"):
    """
    This is where the data is first handled - this would return a div with links, text, etc -
    So, I pass the blurb of text into the parseDiv() function
    """
    item = parseDiv(result)
    results.append(item)

显然，在这一点上，我已经包含了我需要的库...当我提取 soup2 的代码(bs4 的第二个实例在我要处理的新文本简介上)时，只打印我的函数的输入, 一切正常。

这里是错误:

Traceback (most recent call last):
  File "testdata.py", line 29, in <module>
    item = parseDiv(result)
  File "testdata.py", line 17, in parseDiv
    soup2 = BeautifulSoup(text)
  File "C:\Python27\lib\site-packages\bs4\__i
    markup = markup.read()
TypeError: 'NoneType' object is not callable

Answer 1

您不需要再次解析 div。试试这个:

for div in soup.find_all('div', 'res'):
    a = div.find('a', 'yschttl spt')
    if a:
        print a.text
        print
        results.append(a)