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Android 与 WCF Web 服务使用 ksoap2 - 错误 SoapFault - 故障代码 : 'a:InternalServiceFault'

转载 作者:太空宇宙 更新时间:2023-11-03 13:00:05 25 4
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我做了一个简单的项目来使用 ksoap2 调用 wcf web 服务。但是当它调用 envelope.getResponse();它给出了错误的说法

错误:SoapFault - faultcode: 'a:InternalServiceFault' faultstring: '由于内部错误,服务器无法处理请求。有关错误的更多信息,请在服务器上打开 IncludeExceptionDetailInFaults(来自 ServiceBehaviorAttribute 或配置行为)以便将异常信息发送回客户端,或者根据 Microsoft .NET Framework 3.0 SDK 文档打开跟踪并检查服务器跟踪日志。 faultactor:'null' 详细信息:null

package testing.wcf;
import java.io.IOException;
import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapPrimitive;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;
import org.xmlpull.v1.XmlPullParserException;
import org.xmlpull.v1.XmlSerializer;

import android.os.Bundle;
import android.os.StrictMode;
import android.widget.TextView;
import android.annotation.SuppressLint;
import android.app.Activity;

public class MainActivity extends Activity
{
private static final String strNAMESPACE = "http://www.testing.co.in/TestingService/";
private static final String strURL = "http://www.testing.co.in/TestingService/UserDetails.svc";
private static final String strSOAP_ACTION = "http://testing.co.in/TestingService/UserDetails/LoginDetails";
private static final String strMETHOD_NAME = "LoginDetails";
TextView tv;
StringBuilder sb;
String strInputXML;

@Override
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
tv = (TextView)findViewById(R.id.testing);
sb = new StringBuilder();
Call();
tv.setText(sb.toString());
//setContentView(tv);

}
public void Call()
{
try
{
SoapObject request = new SoapObject(strNAMESPACE, strMETHOD_NAME);

String inputxml = "<?xml version="+"\""+"1.0"+"\""+" encoding="+"\""+"utf-8"+"\""+" ?>" +"<MOB> \n <PIN>0000</PIN> \n <LOGINID>TEST</LOGINID> \n <PNUMBER>112233</pNUMBER> \n <REQUESTID>LoginVal</REQUESTID> \n </MOB>";

request.addAttribute("strInputXML", inputxml);
request.addAttribute("strOutputXML","");

SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);

HttpTransportSE androidHttpTransport = new HttpTransportSE(strURL);
androidHttpTransport.call(strSOAP_ACTION, envelope);
SoapPrimitive result = (SoapPrimitive)envelope.getResponse();

String resultData = result.toString();
sb.append(resultData + "\n");
}
catch(Exception e)
{
sb.append("Error:\n" + e.getMessage() + "\n");
}
}
}

这里我想这样发送请求

<?xml version="1.0" encoding="utf-8" ?> 
<PhoneData>
<PINNO>0000</PINNO>
<LOGINID>HELLO</LOGINID>
<PASSWORD>1234</PASSWORD>
<REQID>0</REQID>
</PhoneData>

我的响应 XML 应该是

<?xml version="1.0" encoding="utf-8" ?> 
<PhoneData>
<OTA>1234</OTA>
</PhoneData>

最佳答案

我发布了使用 WCF 的工作代码(WCF 的绑定(bind)必须是 basicHttpBinding!):

private static final String NAMESPACE = "http://tempuri.org/";
private static String URL="your url";

private static final String SOAP_ACTION_VALIDATION = "IValidateUser_wcf/ValidateUser";
private static final String VALIDATION_METHOD = "ValidateUser";

public boolean validateUser_WCF(String username, String password){

SoapSerializationEnvelope envelope = null;
SoapObject request = null;
HttpTransportSE httpTransportSE = null;

try {
request = new SoapObject(NAMESPACE, VALIDATION_METHOD);
request.addProperty("username", username);
request.addProperty("password", password);

envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);

//////////////////////////////
// here you can add a HEADER element if you want
Element[] header = new Element[1];

header[0] = new Element().createElement(NAMESPACE_INFOCAD, "a1");
header[0].addChild(Node.TEXT, "HeaderTextContent");

envelope.headerOut = header;
//////////////////////////////

httpTransportSE = new HttpTransportSE(URL+VALIDATION_URI, 10*10000); // second parameter is timeout
httpTransportSE.debug = true;
httpTransportSE.setXmlVersionTag("<?xml version=\"1.0\" encoding=\"utf-8\"?>");
httpTransportSE.call(NAMESPACE+SOAP_ACTION_VALIDATION, envelope);

// if response is a simple text result, you can call SoapPrimitive, if not, you have to call SoapObject result and navigate in response's tree like an xml file
SoapPrimitive result = (SoapPrimitive)envelope.getResponse();

//To get the data.
String textResult = result.toString();
Log.i("textResult", textResult);

return true;

} catch (Exception e) {
// TODO: handle exception
e.printStackTrace();
}finally{
// here you can see in LOG what is request you send and what is response received
Log.i(getClass().getSimpleName(),"requestDump : "+httpTransportSE.requestDump);
Log.i(getClass().getSimpleName(),"responseDump : "+httpTransportSE.responseDump);
}

return false;
}

希望我的代码能帮到你 :)。它以 100% 的速度工作

关于Android 与 WCF Web 服务使用 ksoap2 - 错误 SoapFault - 故障代码 : 'a:InternalServiceFault' ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12928759/

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