解析格式化字符串并从中获取字典的 Pythonic 方法

Question

我有一个看起来像这样的字符串:

{
    "key A":[
        ["some val", "value a1"],
        ["some val", "value a2"],
        ....................
        ["some val", "value an"]
    ], "key B":[
        ["some val", "value b1"],
        ["some val", "value b2"],
        ...
    ], ...
     , "key X":[
        ["some val", "value x1"],
        ["some val", "value x2"],
        ...
    ]
}

谁能告诉我在 python 中从字典中取出字典的正确方法是什么

{
    "key A": ["val a1", "val a2", ..."val an"],
    "key B": ["val b1", "val b2", ..."val bn"],
    .....
    "key X": ["val x1", "val x2", ..."val xn"],
}

我问这个是因为现在我唯一能想到的代码是一个非常脏的代码，有很多列表、拆分和替换，我很确定这是非常错误的方法:D。非常感谢。

Answer 1

您可以使用 ast.literal_eval 和字典理解:

from ast import literal_eval

mystr = """{
    "key A":[
        ["some val", "value a1"],
        ["some val", "value a2"],
        ["some val", "value an"]
    ], "key B":[
        ["some val", "value b1"],
        ["some val", "value b2"],
    ], "key X":[
        ["some val", "value x1"],
        ["some val", "value x2"],
    ]
}"""

res = {k: list(list(zip(*v))[1]) for k, v in literal_eval(mystr).items()}

# {'key A': ['value a1', 'value a2', 'value an'],
#  'key B': ['value b1', 'value b2'],
#  'key X': ['value x1', 'value x2']}