python - 有没有更好的方法来构建这样的列表？

Question

我是 Python 的新手，我很喜欢它，但想知道是否有更好的方法来进行一些列表操作。

这个相对理智，但似乎我可能错过了一个内置函数。

def zip_plus(source_list, additional_list):
    """
    Like zip but does plus operation where zip makes a tuple

    >>> a = []
    >>> zip_plus(a, [[1, 2], [3, 4]])
    >>> a
    [[1, 2], [3, 4]]
    >>> zip_plus(a, [[11, 12], [13, 14]])
    >>> a
    [[1, 2, 11, 12], [3, 4, 13, 14]]
    """
    if source_list:
        for i, v in enumerate(additional_list):
            source_list[i] += v
    else:
        source_list.extend(additional_list)

这篇文章很骇人听闻，有什么想法可以让它更简洁或更符合 Python 风格吗？

def zip_join2(source_list, additional_list):
    """
    Pretty gross and specialized function to combine 2 types of lists of things,
    specifically a list of tuples of something, list
    of which the something is left untouched

    >>> a = []
    >>> zip_join2(a, [(5, [1, 2]), (6, [3, 4])])
    >>> a
    [(5, [1, 2]), (6, [3, 4])]
    >>> zip_join2(a, [(5, [11, 12]), (6, [13, 14])])
    >>> a
    [(5, [1, 2, 11, 12]), (6, [3, 4, 13, 14])]
    """
    if source_list:
        for i, v in enumerate(additional_list):
            source_list[i] = (source_list[i][0], source_list[i][1] + v[1])
    else:
        source_list.extend(additional_list)

Answer 1

def zip_plus(first, second):
    return [x+y for (x,y) in zip(first, second)]

def zip_join2(first, second):
    return [(x[0], x[1]+y[1]) for (x,y) in zip(first, second)]