Python CTRL-C 退出没有回溯？

Question

构建一个简单的“石头剪刀布”Python 游戏以供学习。

我在这里阅读了其他一些关于在没有回溯的情况下退出 Python 的帖子。我正在尝试实现它，但仍然得到回溯!一些 Python 高手可以指出这个 Python 虚拟机有什么问题吗？这个想法是单击 RETURN(或键入“yes”或“y”将使程序再次运行 play()，但按 CTRL-C 将关闭它而没有回溯。我使用的是 Python 2.7。

    # modules
    import sys, traceback
    from random import choice

    #set up our lists
    ROCK, PAPER, SCISSORS = 1, 2, 3
    names = 'ROCK', 'PAPER', 'SCISSORS'

    #Define a function for who beats who?
    def beats(a, b):
        return (a,b) in ((PAPER, ROCK), (SCISSORS, PAPER), (ROCK, SCISSORS))

    def play():
        print "Please select: "
        print "1 Rock"
        print "2 Paper"
        print "3 Scissors"
        # player choose Rock, Paper or Scissors
        player_choice = int(input ("Choose from 1-3: "))
        # assigns the CPU variable a random CHOICE from a list.
        cpu_choice = choice((ROCK, PAPER, SCISSORS))

        if cpu_choice != player_choice:
            if beats(player_choice, cpu_choice):
                print "You chose %r, and the CPU chose %r." % (names[player_choice - 1], names[cpu_choice - 1])
                print "You win, yay!!"
            else:
                print "You chose %r, and the CPU chose %r." % (names[player_choice - 1], names[cpu_choice - 1])
                print "You lose. Yuck!"
        else:
            print "You chose %r, and the CPU chose %r." % (names[player_choice - 1], names[cpu_choice - 1])
            print "It's a tie!"

        print "Do you want to play again? Click RETURN to play again, or CTRL-C to exit!"

        next = raw_input("> ")

        # THIS IS WHAT I'M WORKING ON - NEED TO REMOVE TRACEBACK!
        if next == "yes" or "y":
            try:
                play()
            except KeyboardInterrupt:
                print "Goodbye!"
            except Exception:
                traceback.print_exc(file=sys.stdout)
            sys.exit(0)
        elif next == None:
            play()
        else:
            sys.exit(0)

# initiate play() !
play()

Answer 1

尝试重构你的主循环；更多类似的内容:

try:
    while (play()):
        pass
except KeyboardInterrupt:
    sys.exit(0)

play 看起来像:

def play():
    _do_play() # code for the actual game

    play_again = raw_input('play again? ')
    return play_again.strip().lower() in ("yes", "y")