c# - XmlSerializer 不使用在类上定义的 XmlRoot

Question

我正在尝试将自定义类序列化为 XML。这是类(class):

[Serializable()]
[XmlRoot("KVP")]
public class SerializableKeyValuePair<TKey, TValue>
{

    public SerializableKeyValuePair()
    { }

    public SerializableKeyValuePair(TKey key, TValue value)
    {
        Key = key;
        Value = value;
    }

    public TKey Key { get; set; }
    public TValue Value { get; set; }

}

这是尝试序列化它的代码:

    var xmlWriter = new StringWriter();
    Type[] extraTypes = new Type[1] { typeof(SerializableKeyValuePair<string, string>) };
    var xmlSerializer = new XmlSerializer(typeof(List<SerializableKeyValuePair<string, string>>), extraTypes);
    xmlSerializer.Serialize(xmlWriter, functions);
    xmlRet = xmlWriter.ToString();

这是实际结果:

<ArrayOfSerializableKeyValuePairOfStringString>
    <SerializableKeyValuePairOfStringString>
        <Key>Min</Key>
        <Value>Min</Value>
    </SerializableKeyValuePairOfStringString>
    <SerializableKeyValuePairOfStringString>
        <Key>MinAvgMax</Key>
        <Value>MinAvgMax</Value>
    </SerializableKeyValuePairOfStringString>
</ArrayOfSerializableKeyValuePairOfStringString>

我想看到的是以下内容，但它似乎没有使用我定义的 XmlRoot。谁能帮我弄清楚如何获得这个 XML 结构？

<ArrayOfKVP>
    <KVP>
        <Key>Min</Key>
        <Value>Min</Value>
    </KVP>
    <KVP>
        <Key>MinAvgMax</Key>
        <Value>MinAvgMax</Value>
    </KVP>
</ArrayOfKVP>

TIA!

Answer 1

但是SerializableKeyValuePair不是根，List<SerializableKeyValuePair<string, string>>是!

我认为您正在寻找 XmlType :

[XmlType("KVP")]
public class SerializableKeyValuePair<TKey, TValue>
{
    //...
}

如果您想更改列表的元素名称，您可以提供 XmlRootAttribute创建序列化程序时:

var serializer = new XmlSerializer(typeof(List<SerializableKeyValuePair<string, string>>), 
    null, extraTypes, new XmlRootAttribute("ArrayOfKVP"), string.Empty);

顺便说一句，Serializable与XmlSerializer无关.除非您出于其他目的需要它，否则可以将其删除。