c# - WPF 组合框 : click outside of popup suppress mouse click

Question

我使用标准的 WPF ComboBox 控件。当弹出窗口打开并且用户单击外部某处时，弹出窗口将关闭。但是如果窗口上有按钮并且用户单击它(弹出窗口仍然打开)，则不会执行按钮的单击处理程序。弹出窗口已关闭，但用户必须再点击一次按钮才能引发点击事件。

我知道这是该控件的标准行为。你有什么想法如何绕过这种行为吗？谢谢!

Answer 1

我用@Eng 修复了一些错误。 M·哈姆迪 very good approach并在 C# 中完成，还将其应用于应用程序范围内的所有组合框。

应用 Hook :

EventManager.RegisterClassHandler(typeof(ComboBox), UIElement.PreviewMouseLeftButtonDownEvent, new MouseButtonEventHandler(FixComboBoxOutClick));

处理程序代码:

    private void FixComboBoxOutClick(object sender, MouseButtonEventArgs e) {
        if (sender is ComboBox combo) {
            Point comboRelativePoint = Mouse.GetPosition(combo);
            if (comboRelativePoint.X < 0 || comboRelativePoint.Y < 0 || comboRelativePoint.X > combo.ActualWidth || comboRelativePoint.Y > combo.ActualHeight) {
                UIElement popupContent = combo.FindChild<Popup>(null).Child;
                Point popupRelativePoint = Mouse.GetPosition(popupContent);
                if (popupRelativePoint.X < 0 || popupRelativePoint.Y < 0 || popupRelativePoint.X > popupContent.RenderSize.Width || popupRelativePoint.Y > popupContent.RenderSize.Height) {
                    combo.IsDropDownOpen = false;
                }
            }
        }
    }

可以找FindChild<T>()实现 here .