python 字符串替换错误地删除了空格

Question

我有一个方法

def strip_searchname(self, original_name):
    taboo = {" and ", " of ", " at ", " in ", ":", "-", ",", " the ", " "}
    searchname = original_name
    for word in taboo:
        print(searchname)
        searchname = searchname.replace(word, "")
    searchname = re.sub('[^a-zA-Z]', "", searchname)
    searchname= searchname.upper()
    return searchname

(是的，我知道部分内容是多余的)

第一个 .replace 似乎去除了整个字符串的空白，这是我不想要的。为什么是这样？我该如何避免？

(例如输出是:

Seattle University
SeattleUniversity
SeattleUniversity
SeattleUniversity
SeattleUniversity
SeattleUniversity
SeattleUniversity
SeattleUniversity
SeattleUniversity
SEATTLEUNIVERSITY

)

Answer 1

What I DON'T understand is why it seems to be executing the " " replace BEFORE the " of " replace, for example, when the " of " replace comes before the space in the list.

这不是一个列表。

taboo = {" and ", " of ", " at ", " in ", ":", "-", ",", " the ", " "}

是一个集合文字。尝试用 [ 和 ] 替换 { 和 } 以获得您想要的顺序。