python嵌套字典循环

Question

是否有更好/更清洁/更短的方法来获得与以下相同的输出？

import plistlib
pl = plistlib.readPlist('/Users/username/Documents/wifi1.plist')

n = len(pl)
count = 0
while (count < n):
    print('----------------')
    print(pl[count]['NOISE'])
    print(pl[count]['RSSI'])
    print(pl[count]['SSID_STR'])
    print(pl[count]['BSSID'])
    count += 1

我试过:

for sub_dict in pl.values():
    print(sub_dict['NOISE'], sub_dict['RSSI'], sub_dict['SSID_STR'], sub_dict['BSSID'])

但我得到:

Traceback (most recent call last):
  File "plistread.py", line 17, in <module>
    for sub_dict in pl.values():
AttributeError: 'list' object has no attribute 'values'

Answer 1

你只需要:

for sub_dict in pl:

因为 pl 是一个列表，遍历该列表将依次为您提供每个子字典。

一个简单的例子:

>>> l = [1,2,3,4]
>>> for x in l:
...   print x,
... 
1 2 3 4