python - 如何在 bash 中解析 json 或将 curl 输出传递给 python 脚本

Question

我正在寻找一些方法来在 json 中漂亮地打印 curl 的输出。我为此编写了简短的 python 脚本，但它不适用于管道我也不想使用子进程并从它们运行 curl:

所以 python :

#!/usr/bin/python

import simplejson
from pprint import pprint
import sys
print pprint(simplejson.loads(sys.argv[1]))

而json信息是:

{"response": {"utilization": {"eic": [{"date": "2012.03.06", "usage": []}, {"date": "2012.03.07", "usage": [{"srvCode": "SVC302", "upload": 267547188, "api-calls": {"fileGetInfo": 30, "getUserStorageQuota": 0, "setUserStorageQuota": 0, "fileUploadFlashInit": 31, "getAPISessionUser": 0, "setFileAccessControl": 0, "fileGetPreviewUrl": 0, "fileStartMultipartUpload": 0, "getServiceQuota": 0, "fileGetPreviewUrlsForBunch": 10, "xcodingGetStreamUrl": 0, "getSessionTimeLimit": 0, "fileGetCoversUrlsForBunch": 27, "makePreviews": 0, "setServiceQuota": 0, "getAPISessionTrusted": 3, "getFileAccessControl": 0, "xcodingGetFormats": 0, "getQuotaNotificationEmail": 0, "fileGetDownloadUrl": 0, "xcodingGetStreamInfo": 0, "fileUploadDone": 30, "getLocalServiceUtilization": 9, "getServiceUtilization": 0, "fileDelete": 19, "setSessionTimeLimit": 0, "fileGetMultipartUploadUrl": 0, "fileUploadInit": 0, "extractFileMetadata": 30, "setQuotaNotificationEmail": 0}, "average-storage": 3801210959.4961309, "download": 0, "transcoding": 0}]}]}}}

Answer 1

使用 shell 中的 json.tool 来验证和 pretty-print :

$ echo '{"json":"obj"}' | python -mjson.tool
{
    "json": "obj"
}