android - 如何在 Phonegap 3.4.0 上以编程方式退出应用程序？

Question

我正在使用 JQuery Mobile 和 Phonegap 3.4.0 (Apache cordova) 开发一个 android 应用程序。我试图以编程方式关闭应用程序，所以我尝试了:

navigator.app.exitApp();

和

navigator.device.exitApp();

这是 ondeviceready 文档监听器:

document.addEventListener("deviceready", onDeviceReady(), true);
function onDeviceReady() {
    var today = new Date();
    var dd = today.getDate();
    if(dd==15) {
        alert("Your application has been expired");
        navigator.app.exitApp();
    }
}

我直接在我的 android 手机上运行该应用程序，当我尝试检查 navigator.app 的值时，我得到了 undefined

Answer 1

确保正确安装网络phonegap插件

cordova plugin add https://github.com/apache/cordova-plugin-network-information

然后使用这段代码

document.addEventListener("deviceready", onDeviceReady, false);
// device APIs are available
//

function onDeviceReady() {
    checkConnection();
}

function checkConnection() {
    var networkState = navigator.connection.type;
    var states = {};
    states[Connection.UNKNOWN] = 'Unknown connection';
    states[Connection.ETHERNET] = 'Ethernet connection';
    states[Connection.WIFI] = 'WiFi connection';
    states[Connection.CELL_2G] = 'Cell 2G connection';
    states[Connection.CELL_3G] = 'Cell 3G connection';
    states[Connection.CELL_4G] = 'Cell 4G connection';
    states[Connection.CELL] = 'Cell generic connection';
    states[Connection.NONE] = 'No network connection';
    if ((states[networkState]) == states[Connection.NONE]) {
        alert('No Internet Connection. Click OK to exit app');
        navigator.app.exitApp();
    }
}