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php - 如何使用 codeigniter 存储图像并从文件夹中检索图像?

转载 作者:太空宇宙 更新时间:2023-11-03 12:26:34 24 4
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我是 CodeIgniter 编程的新手。我想从文件夹中存储和检索图像。但是当我运行代码时,我发现错误如下:

第一个错误:

Upload failed!

A PHP Error was encountered

Severity: Notice

Message: Undefined variable: in

Filename: controllers/main.php

Line Number: 104

第二个错误:

A Database Error Occurred

You must use the "set" method to update an entry.

Filename: application/models/main_model.php

Line Number: 80

我正在使用这段代码:

在控制中:

<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
class Main extends CI_Controller{
public function __construct()
{
parent::__construct();
$this->load->model('main_model');
$this->load->helper(array('form', 'url'));
}
public function product()
{
$this->load->library('form_validation');
$this->form_validation->set_rules('productname','Product Code','trim|required');
$this->form_validation->set_rules('productcode','Product Code','trim|required');
$this->form_validation->set_rules('productprice','Product Price','trim|required');
$this->form_validation->set_rules('quantity','Quantity','trim|required');
$this->form_validation->set_rules('uploadimage','Upload Image','trim|required');
if($this->form_validation->run()==FALSE)
{
$this->index();
}else
{
if ($this->input->post('upload'))
{
$in=array();

$in['productname'] = $this->input->post('productnamename');
$in['productcode'] = $this->input->post('productcode');
$in['productprice']=$this->input->post('productprice');
$in['quantity']=$this->input->post('quantity');
$in['uploadimage']=$_FILES['image']['name'];
}
if($this->main_model->do_upload()) {

echo $this->upload->display_errors();

}else
{
$this->main_model->save_gallery($in);
header('location:product');
}
$data['images']=$this->main_model->get_images();
$this->load->view('query_view',$data);
}
}

在模型中:

 <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
class Main_model extends CI_Model {
public function __construct()
{
parent::__construct();
}
public function do_upload()
{
$config = array(
'allowed_types' => 'jpg|png|bmp',
'upload_path'=>'./uploads/', //make sure you have this folder
'max_size'=>2000);
$this->load->library('upload',$config);

if ($this->upload->do_upload()) {
echo "Upload success!";
} else {
echo "Upload failed!";
}
$image_data = $this->upload->data();
}
function get_images()
{
$query = $this->db->get('product');
return $query;
}

function save_gallery($in)
{
$save=$this->db->get("product");
if($save->num_rows())
{
$save=$this->db->insert('product',$in);
return $save;
}
}

在 View 中:

 <?php foreach ($images as $image):?>
<h1><?php echo $image['a_name'];?></h1>
<h1><?php echo $image['a_details'];?></h1>
<?php echo '<img src ="'. base_url().'images1/'.$image['a_photo'].'" >";
endforeach; ?>

首页 View :

<?php echo form_open("main/product"); ?>
<p>
<label for="product_name">Product Name:</label>
<input type="text" id="productname" name="productname" value="<?php echo set_value('product_name'); ?>" />
</p>


<p>
<label for="ProductCode">Product Code</label>
<input type="text" id="productcode" name="productcode" value="<?php echo set_value('productcode'); ?>" />
</p>
<p>
<label for="productprice">Product Price:</label>
<input type="text" id="productprice" name="productprice" value="<?php echo set_value('productprice'); ?>" />
</p>
<p>
<label for="Quantity">Quantity:</label>
<select name="quantity" id="quantity" value="<?php echo set_value('quantity'); ?>" /><option>1</option>
<option>2</option>
<option>3</option>
<option>4</option>
<option>5</option>
</select>

</p>
<p>
<label for="Uploadimage">Upload Image:</label>
<input type="file" name="uploadimage" id="uploadimage" value="<?php echo set_value('uploadimage'); ?>" />
</p>

<p>
<input type="submit" class="greenButton" value="submit" />
</p>
<?php echo form_close(); ?>

最佳答案

首先,阅读 http://ellislab.com/codeigniter/user-guide/libraries/file_uploading.html 上的文档.逐字逐句,没有什么花哨的,没有数据库,没有额外的条件。让它工作并以非常小的部分增量添加新功能。当你遇到问题时,四处寻找答案。

现在问题来了..

您没有获得 $this->input->post('upload') 的值这只是众多问题中的一个。

你的表单打开应该是

<?php echo form_open_multipart("main/product"); ?>

下面的错误通常表示您正在将一个空变量传递给 insert功能

A Database Error Occurred

You must use the "set" method to update an entry.

Filename: application/models/main_model.php

Line Number: 80

为什么要传递一个空变量?您正在调用 do_upload始终返回 void 的方法,因此,TRUE下面的代码永远不会满足条件。

if($this->main_model->do_upload()) {
echo $this->upload->display_errors();
}
else
{
$this->main_model->save_gallery($in);
header('location:product');
}

验证您正在传递名为 upload 的输入在表单中,上传的条件应该更像这样

    if(isset($_FILES['upload']['name']))
{
$in=array();

$in['productname'] = $this->input->post('productnamename');
$in['productcode'] = $this->input->post('productcode');
$in['productprice']=$this->input->post('productprice');
$in['quantity']=$this->input->post('quantity');
$in['uploadimage']=$_FILES['image']['name'];

// moved to inside the post('upload') conditional
if($this->main_model->do_upload()) {
echo $this->upload->display_errors();
}
else
{
$this->main_model->save_gallery($in);
header('location:product');
}

}

关于php - 如何使用 codeigniter 存储图像并从文件夹中检索图像?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17320640/

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