mysql - 计算一周中每一天的出现次数

Question

我有这张表:

| name | gender | date             |
------------------------------------
| Foo  | male   | 2013-09-16 10:23 |
| Name | male   | 2013-09-16 09:10 |
| Red  | male   | 2013-09-15 09:10 |
| Bar  | female | 2013-09-15 10:10 |
etc...

我需要获取按性别过滤的一周中每一天的访问次数。

所以我应该得到，如果我算上男性:

1: 2 visits
2: 0 visits
3: 0 visits
4: 0 visits
5: 0 visits
6: 0 visits
7: 1 visit

查询应该是:

SELECT FROM table
WHERE gender = 'male'
GROUP BY DAYOFWEEK

我的查询不起作用，所以我想问问是否有人知道如何让它起作用...

Answer 1

尝试

SELECT dayofweek(date) dayofweek, gender, count(*) count
FROM table
GROUP BY DAYOFWEEK(date), gender

编辑:

如果你想把星期一设为 1，星期日设为 7，你也可以这样做

SELECT (dayofweek(date)+5)%7+1 dayofweek, gender, count(*) count
FROM table
GROUP BY (dayofweek(date)+5)%7+1, gender

如果你想避免 if 结构......