python - 使用 python 正则表达式从字符串中单独提取子字符串

Question

我正在尝试编写一个正则表达式，它返回字符串之后的子字符串的一部分。例如:我想获取子字符串的一部分以及位于“15/08/2017”之后的空格。

a='''S
LINC             SHORT LEGAL                                   TITLE NUMBER
0037 471 661     1720278;16;21                                 172 211 342

LEGAL DESCRIPTION
PLAN 1720278  
BLOCK 16  
LOT 21  
EXCEPTING THEREOUT ALL MINES AND MINERALS  

ESTATE: FEE SIMPLE  
ATS REFERENCE: 4;24;54;2;SW

MUNICIPALITY: CITY OF EDMONTON

REFERENCE NUMBER: 172 023 641 +71

---------------------------------------------------------------------------- 
----
             REGISTERED OWNER(S)
REGISTRATION    DATE(DMY)  DOCUMENT TYPE      VALUE           CONSIDERATION
--------------------------------------------------------------------------- 
-- 
---

172 211 342    15/08/2017  AFFIDAVIT OF                       CASH & MTGE'''

有没有办法将 'AFFIDAVIT OF' 和 'CASH & MTGE' 作为单独的字符串获取？

这是我到目前为止拼凑的表达式:

doc = (a.split('15/08/2017', 1)[1]).strip()
'AFFIDAVIT OF                       CASH & MTGE'

Answer 1

不是基于正则表达式的解决方案。但是有诀窍。

a='''S
LINC             SHORT LEGAL                                   TITLE NUMBER
0037 471 661     1720278;16;21                                 172 211 342

LEGAL DESCRIPTION
PLAN 1720278  
BLOCK 16  
LOT 21  
EXCEPTING THEREOUT ALL MINES AND MINERALS  

ESTATE: FEE SIMPLE  
ATS REFERENCE: 4;24;54;2;SW

MUNICIPALITY: CITY OF EDMONTON

REFERENCE NUMBER: 172 023 641 +71

---------------------------------------------------------------------------- 
----
            REGISTERED OWNER(S)
REGISTRATION    DATE(DMY)  DOCUMENT TYPE      VALUE           CONSIDERATION
--------------------------------------------------------------------------- 
-- 
---

172 211 342    15/08/2017  AFFIDAVIT OF                       CASH & MTGE'''

doc = (a.split('15/08/2017', 1)[1]).strip() 
# used split with two white spaces instead of one to get the desired result
print(doc.split("  ")[0].strip()) # outputs AFFIDAVIT OF
print(doc.split("  ")[-1].strip()) # outputs CASH & MTGE

希望对您有所帮助。