python - python中日期的迭代器

Question

我有一个 begin_date datetime.date(2012, 9, 1) 和一个 end_date datetime.date(2012, 9, 30)

我想要一个迭代器或一个包含日期 2012/9/1 到 2012/9/30 的列表。除了循环之外还有什么方法可以生成迭代器或列表

Answer 1

使用生成器:

from datetime import date, timedelta

def dategenerator(start, end):
    current = start
    while current <= end:
        yield current
        current += timedelta(days=1)

演示:

>>> for dt in dategenerator(date(2012, 9, 1), date(2012, 9, 30)):
...     print dt
... 
2012-09-01
2012-09-02
2012-09-03
2012-09-04
2012-09-05
2012-09-06
2012-09-07
2012-09-08
2012-09-09
2012-09-10
2012-09-11
2012-09-12
2012-09-13
2012-09-14
2012-09-15
2012-09-16
2012-09-17
2012-09-18
2012-09-19
2012-09-20
2012-09-21
2012-09-22
2012-09-23
2012-09-24
2012-09-25
2012-09-26
2012-09-27
2012-09-28
2012-09-29
2012-09-30