c# - 显示 SSH.NET 的输出

Question

我是 C# 的新手，我正在尝试使用 SSH.NET 框架编写 SSH 控制台应用程序。到目前为止，我能够成功连接到我的服务器，但现在我正在尝试运行命令并让它显示结果。然而，当我运行我的应用程序时，我的控制台是空白的。我的最终目标是执行一组命令并在命令结束时查看结果。

Program.cs

using Renci.SshNet;
class Program
{
    //Login Parameter
    const String Hostname = "somePort";
    const int PortNumber = 22;
    const String Username = "username";
    const String Password = "root";

    static void Main(string[] args)
    {
        //Bypass Keyboard authentication
        KeyboardInteractiveAuthenticationMethod kauth = new KeyboardInteractiveAuthenticationMethod(Username);
        PasswordAuthenticationMethod pauth = new PasswordAuthenticationMethod(Username, Password);
        kauth.AuthenticationPrompt += new EventHandler<Renci.SshNet.Common.AuthenticationPromptEventArgs>(HandleKeyEvent);

        //Grab info for connections
        ConnectionInfo connectionInfo = new ConnectionInfo(Hostname, PortNumber, Username, pauth, kauth);

        //Connect
        using (SshClient client = new SshClient(connectionInfo))
        {
            try
            {
                //Connect to server
                client.Connect();
                Console.WriteLine("Connection successful");

                var command = client.CreateCommand("ls");
                var result = command.Execute();
                command.Execute();
                Console.WriteLine(result);

                //Disconnect from server
                client.Disconnect();
            }
            //Show exp message
            catch (Exception exp)
            {
                throw exp;
            }
        }       
    }

    //Handle two step auth
    static void HandleKeyEvent(Object sender, Renci.SshNet.Common.AuthenticationPromptEventArgs e)
    {
        foreach (Renci.SshNet.Common.AuthenticationPrompt prompt in e.Prompts)
        {
            if (prompt.Request.IndexOf("Password:", StringComparison.InvariantCultureIgnoreCase) != -1)
            {
                prompt.Response = Password;
            }
        }
    }
}

Answer 1

我不知道你是否已经解决了这个问题，但在这种情况下解决方案很简单。函数:

command.Execute()

不返回您的结果。您必须像以前那样执行，然后通过

获取结果

command.Result 

它看起来像这样:

 var command = client.CreateCommand("ls");
 command.Execute();
 var result = command.Result;

希望能帮到你。