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php - 发现错误 : “Column count doesn' t match value count at row 1”

转载 作者:太空宇宙 更新时间:2023-11-03 12:13:40 25 4
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我认为错误应该是插入字段中的数字与值中的数字不匹配,但我真的看不出我的代码有什么问题。错误是“这是错误:列数与第 1 行的值数不匹配”,这表明我的插入有问题:

<?

$con2=mysqli_connect("localhost","root","","test");

if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

$result2= mysqli_query($con2,"SELECT projects.*, org.orgname FROM projects left outer join org on projects.orgid = org.orgid where projects.projectid = '".$projectid."'");
$row2 = mysqli_fetch_array($result2);

$con3 = mysql_connect("localhost","root","");
if (!$con3)

{

die('Could not connect: ' . mysql_error());

}
mysql_select_db("test", $con3);
echo $row2[target];

$sql3 = "INSERT INTO projectlog
(projectid,projectname,generaluserid,adminuserid,swdfphase,target,objective,type,projectsize,commonth,comyear,duration,detail,projectstatus,projectsatisfaction,overallcomments,projectbenefits,orgid,createtime,lastupdatetime,logcreatetime,userid)
VALUES
('".$projectid."',
'".$row2[projectname]."',
'".$row2[generaluserid]."',
'".$row2[adminuserid]."',
'".$row2[swdfphase]."',
'".$row2[target]."',
'".$row2[objective]."',
'".$row2[type]."',
'".$row2[projectsize]."',
'".$row2[commonth]."',
'".$row2[comyear]."',
'".$row2[duration]."',
'".$row2[detail]."',
'".$row2[projectstatus]."',
'".$row2[projectsatisfaction]."',
'".$row2[overallcomments]."',
'".$row2[projectbenefits]."'
'".$row2[orgid]."',
'".$row2[createtime]."',
'".$row2[lastupdatetime]."',
now(),
'".$_SESSION[myid]."')";

if (!mysql_query($sql3,$con3))

{

die('Here is the error: ' . mysql_error());

}




mysql_close($con3);

?>

最佳答案

看起来你在行尾少了一个逗号

'".$row2[projectbenefits]."'

关于php - 发现错误 : “Column count doesn' t match value count at row 1”,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23126662/

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