php - 什么是 "Array to string error"？

Question

$data = mysql_query(" SELECT * FROM user_pokemon_db WHERE user_id = '".$id."' ");
while($rows = mysql_fetch_array($data))
{ 
 $pkmn_id = $rows['pkmn_id'];
 $path = mysql_query(" SELECT path FROM pokemons WHERE pk_id = '".$pkmn_id."' ");
 $poke = mysql_result($path, 0, "path");
 echo $poke; 
 echo "<br />";
 $level = $rows['level']; 
 echo $level;
 echo "<br />";
 $exp = $rows['exp']; 
 echo $exp;

这是我的 PHP 代码，显示错误:C:\wamp\www\slots.php第18行数组到字符串的转换

Line 18 is this:while($rows = mysql_fetch_array($data)) 

我没有用过任何数组？？但这曾经有效!但是突然间这个错误开始出现了？？

Answer 1

检查$id是不是数组，好像是这个问题导致的。

$id = "'" . implode("', '", $id) . "'";
$data = mysql_query(" SELECT * FROM user_pokemon_db WHERE user_id IN ({$id}) ");