android - HTTP POST 请求 ANDROID 4(在 2.3 中工作)？

Question

好吧，事情就是这样，我编写了一个应用程序，它通过 HTTP(发布)请求来自 Web url 的数据，数据使用 JSon 数组返回，我解析这些数组以获得我想要的。

直到使用 android 2.3.x 没有问题，但是当我在 Android 4 中测试它时，它根本不起作用。

这是我的代码:

public boolean testConexio(){

    boolean status = false;

    String rutaServer = "URL.php";
    //Log.e("log_tag", "Ruta server: "+rutaServer);
    InputStream is = null;
    String result = "";
    String temporal;

    //Valors a demanar/enviar
    ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
    nameValuePairs.add(new BasicNameValuePair("param1",config.getUserDB())); // parametros POST!
    nameValuePairs.add(new BasicNameValuePair("param2",config.getPassDB())); // parametros POST!

    //http post
    try{
        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost(rutaServer);
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs,"UTF-8")); // valors POST UTF 8 coded <-- I KNOW! this is the way i need them spanishfag here
        HttpResponse response = httpclient.execute(httppost);
        HttpEntity entity = response.getEntity();
        is = entity.getContent();
    }catch(Exception e){
        Log.e("log_tag", "Error in http connection "+e.toString());
    }

    //Convierte la respuesta a String
    try{
        BufferedReader reader = new BufferedReader(new InputStreamReader(is,"UTF-8"),8); // again, spanishfag here
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
        is.close();
        result=sb.toString();
    }catch(Exception e){
        Log.e("log_tag", "Error converting result "+e.toString());
    }

    //Parse la respuesta JSon
    try{
        JSONObject jArray = new JSONObject(result);
        temporal = jArray.getString("status");
        if(temporal.equals("true")){
            status = true;
        }
        Log.i("log_tag","Status: "+jArray.getString("status"));
    }catch(JSONException e){
        Log.e("log_tag", "Error parsing data "+e.toString());
    }

    return status;
}

谁能告诉我我做错了什么？或者我需要更改的内容，我现在一直在搜索，但我无法让它在 Android 4 上运行。

谢谢!

Answer 1

你需要把它放在一个Async任务中，它不会在3.0的主线程中运行>

使用这个:

public class PostTask extends AsyncTask<Void, String, Boolean> {

        @Override
        protected Boolean doInBackground(Void... params) {
            boolean result = false;

            //All your code goes in here 

            //If you want to do something on the UI use progress update

            publishProgress("progress");
            return result;
        }

        protected void onProgressUpdate(String... progress) {
            StringBuilder str = new StringBuilder();
                for (int i = 1; i < progress.length; i++) {
                    str.append(progress[i] + " ");
                }

        }
    }

你需要在异步任务之外引用它

PostTask posttask;

那么你需要启动它

posttask = new PostTask();
posttask.execute();

几天前我遇到了完全相同的问题，祝你好运