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android - 获取android联系人详细信息非常慢

转载 作者:太空宇宙 更新时间:2023-11-03 12:09:02 25 4
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我的应用程序有一个由设备上注册的联系人填充的 ListView ,但是当我加载 ListView 时,它花费的时间太长了!这是我的代码:

public List<Contact> getContactsList(Context context, ContentResolver contentResolver) {

List<Contact> listContatos = new ArrayList<Contact>();
Uri uri = ContactsContract.Contacts.CONTENT_URI;

Cursor cursorContacts = contentResolver.query(uri, null, null, null, ContactsContract.Contacts.DISPLAY_NAME + " COLLATE NOCASE ASC;");
try {
// while there is a next contact, retrieves your data
while (cursorContacts.moveToNext()) {

Contact c = getContact(context, cursorContacts);

if (c != null) {
listContatos.add(c);
}
}
} finally {

// Closes Cursor
cursorContacts.close();
}
return listContatos;
}





public Contact getContact(Context context, Cursor contactsCur) {

Contact c = new Contact();

// get contact id
long id = contactsCur.getLong(contactsCur.getColumnIndexOrThrow(BaseColumns._ID));
String strId = contactsCur.getString(contactsCur.getColumnIndex(BaseColumns._ID));

// get contact name
String name = contactsCur.getString(contactsCur.getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME));

boolean temFone = false;
// if return is different than 1, doesn't has phone number
temFone = "1".equals(contactsCur.getString(contactsCur.getColumnIndexOrThrow(ContactsContract.Contacts.HAS_PHONE_NUMBER)));
if (temFone) {
contactsCur = context.getContentResolver().query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?",
new String[] { strId }, null);

ArrayList<PhoneNumber> phones = new ArrayList<PhoneNumber>();
while (contactsCur.moveToNext()) {

int idx = contactsCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER);

if (idx != -1) {
String phoneNumber = contactsCur.getString(contactsCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
int phonetype = contactsCur.getInt(contactsCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.TYPE));
String customLabel = contactsCur.getString(contactsCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.LABEL));
String phoneLabel = (String) ContactsContract.CommonDataKinds.Phone.getTypeLabel(context.getResources(), phonetype, customLabel);

phones.add(new PhoneNumber(phoneLabel, phoneNumber));
}
}
c.setPhones(phones);

contactsCur.close();
} else {
c.setPhones(null);
}

loadAddress(context, c, id);
c.setContactId(id);
c.setName(name);
loadEmails(context, c, id);
loadPhotoUri(context, c, id);
return c;
}







private void loadEmails(Context context, Contact c, long id) {

Cursor cursor = context.getContentResolver().query(
ContactsContract.CommonDataKinds.Email.CONTENT_URI, null,
ContactsContract.CommonDataKinds.Email.CONTACT_ID + " = " + id,
null, null);

ArrayList<ContactMail> emails = new ArrayList<ContactMail>();
while (cursor.moveToNext()) {
int idx = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA);

if (idx != -1) {
String stremail = cursor.getString(idx);

int emailtype = cursor.getInt(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Email.TYPE));
String customLabel = cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Email.LABEL));
String emailLabel = (String) ContactsContract.CommonDataKinds.Email.getTypeLabel(context.getResources(), emailtype, customLabel);

if (!stremail.equals(""))
emails.add(new ContactMail(stremail, emailLabel));
}
}
c.setEmails(emails);
cursor.close();

}

private void loadAddress(Context context, Contact c, long id) {

Cursor cursor = context.getContentResolver().query(
ContactsContract.CommonDataKinds.StructuredPostal.CONTENT_URI, null, ContactsContract.CommonDataKinds.StructuredPostal.CONTACT_ID + " = " + id, null, null);

ArrayList<Address> addresses = new ArrayList<Address>();
while (cursor.moveToNext()) {
int idx = cursor.getColumnIndex(ContactsContract.CommonDataKinds.StructuredPostal.DATA);

if (idx != -1) {
String address = cursor.getString(idx);

int addresstype = cursor.getInt(cursor.getColumnIndex(ContactsContract.CommonDataKinds.StructuredPostal.TYPE));
String customLabel = cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.StructuredPostal.LABEL));
String addressLabel = (String) ContactsContract.CommonDataKinds.StructuredPostal.getTypeLabel(context.getResources(), addresstype, customLabel);

if (!address.equals(""))
addresses.add(new Address(address, addressLabel, null));


}
}
c.setAddresses(addresses);
cursor.close();
}

public void loadPhotoUri(Context context, Contact c, long id) {

Cursor cursor = context.getContentResolver().query(ContactsContract.Data.CONTENT_URI,
null,
ContactsContract.Data.CONTACT_ID
+ "="
+ id
+ " AND "

+ ContactsContract.Data.MIMETYPE
+ "='"
+ ContactsContract.CommonDataKinds.Photo.CONTENT_ITEM_TYPE
+ "'", null, null);

while (cursor.moveToNext()) {
int idx = cursor
.getColumnIndex(ContactsContract.CommonDataKinds.SipAddress.DATA);

if (idx != -1) {
Uri person = ContentUris.withAppendedId(
ContactsContract.Contacts.CONTENT_URI, id);
c.setPhoto( Uri.withAppendedPath(person,
ContactsContract.Contacts.Photo.CONTENT_DIRECTORY));
}
}
}

它工作得很好,完美,唯一的问题是获取所有联系人信息需要很长时间。我使用 getContact 方法获取有关设备中每个联系人的所有详细信息,而不是在 getContactsList 中我将其放入联系人列表中。 Contact 列表由 listView 的适配器使用。

提前致谢!

抱歉任何英文错误...

最佳答案

我遇到了同样的问题。必须显示所有联系人姓名和电话号码 - 效果很好,但耗时太长。

作为 Android 开发领域的新手,我对其进行了一些研究并发现了以下帖子:

这对我很有用。

我认为问题在于您正在进行内部查询,所以它会花费您很长时间。我的代码的主要问题是多次获取列索引(所以我将其更改为一次,就在 while 循环之前),以及我在代码中使用的不太清楚的内部查询,并找到了一种方法来拿出来。

尝试使用该帖子中的示例,看看它是否有帮助(希望它会 - 因为对我来说它是完美的!)

祝你好运

关于android - 获取android联系人详细信息非常慢,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17798613/

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