PHP : return last inserted Id on statement

Question

所以我想从查询中获取并返回最后插入的 ID。我成功地获得了最后插入的 id，但是在尝试将它返回到 index.php 文件时我遇到了一个小问题

这是我的方法代码:

        public function InsertUserCard(UserCard $uc)
        {
            if(!$this->DuplicateUserCard($uc))
            {
                $stmt = $this->conn->prepare("INSERT INTO ".$this->table_name."
                                             (user_id, card_id, barcode, barcode_format, created_at, updated_at) 
                                             VALUES(?, ?, ?, ?, ?, ?)");
                if ($stmt == FALSE)
                {
                    die($this->conn->error);
                }
                else  
                {
                    $user_id = NULL;
                    $card_id = NULL;
                    $barcode = NULL;
                    $barcode_format = NULL;
                    $created_at = NULL;
                    $updated_at = NULL;
                    $stmt->bind_param("iissss", $user_id, $card_id, $barcode, $barcode_format, $created_at, $updated_at);
                    $user_id = $uc->getUserId();
                    $card_id =  $uc->getCardId();
                    $barcode = $uc->getBarcode();
                    $barcode_format = $uc->getBarcodeFormat();
                    $created_at = $uc->getCreatedAt();
                    $updated_at = $uc->getUpdatedAt();

                    $stmt->execute();
                    $result = $this->conn->insert_id;   <-- This is how I get the last inserted id
                    $stmt->close();
                }

                // Check for successful insertion
                if ($result) 
                {
                    // User card successfully inserted
                    return USER_CARD_INSERTED_SUCCESSFULLY;
                } 
                else 
                {
                    // Failed to insert user card
                    return USER_CARD_INSERT_FAILED;
                }
            }
            else
            {
                return USER_CARD_ALREADY_EXISTED;
            }
        }

这是我的 index.php 文件

$app->post('/user/card/rev', 'authenticate', function() use ($app) 
{
            // check for required params
            verifyRequiredParams(array('user_id', 'card_id', 'barcode', 'barcode_format', 'created_at', 'updated_at'));

            global $user_id;

            $response = array();
            $timestamp = time();
            $now = date("Y-m-d H:i:s", $timestamp);
            $uc = new UserCard();
            $uc->setUserId($user_id);
            $uc->setCardId($app->request->post('card_id'));
            $uc->setBarcode($app->request->post('barcode'));
            $uc->setBarcodeFormat($app->request->post('barcode_format'));
            $uc->setCreatedAt($app->request->post('created_at'));
            $uc->setUpdatedAt($app->request->post('updated_at'));


            // choose card from db by user
            $UserCardDB = new UserCardDB(MySqlDb::getInstance()->connect());
            $UserCard = $UserCardDB->InsertUserCard($uc);

            if ($UserCard == USER_CARD_INSERTED_SUCCESSFULLY) 
            {
                $response["error"] = false;
                $response["message"] = "User Card added successfully";
                $response["current_timestamp"] = $timestamp;
                $response["current_date"] = $now;
                $response["last_inserted_id"] = SHOULD_BE_HERE;
                echoRespnse(201, $response);
            } 

});

如您所见，我想将最后插入的 ID 放在 $response["last_inserted_id"] 上，但我不知道该怎么做。

有什么想法吗？

谢谢:)

Answer 1

我认为你的陈述倒退了

$inserted_id = $this->conn->insert_id;
$result = $stmt->execute();

在准备好的语句中，execute 是运行您的 SQL 的。所以你无法获取尚未插入的内容的 ID。

$result = $stmt->execute();
$inserted_id = $this->conn->insert_id;

您也没有将数据存储在任何可用的地方($inserted_id 是您函数的局部变量)。考虑创建一个类似 $this->inserted_id 的类变量，并创建一个返回该值的函数。