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php - $_POST 未插入数据库 - PHP MySQL

转载 作者:太空宇宙 更新时间:2023-11-03 12:03:07 24 4
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这是我用于向表中添加数据的 HTML 表单:

<div class="TTWForm-container">
<div id="form-title" class="form-title field"><h2>ახალი სტატია</h2></div>
<form enctype="multipart/form-data" action="index.php?link=addart" class="TTWForm ui-sortable-disabled" method="post">
<div id="field2-container" class="field f_100 ui-resizable-disabled ui-state-disabled">
<label for="title">სათაური</label>
<input name="title" id="title" required="required" type="text">
</div>
<div id="field10-container" class="field f_100 ui-resizable-disabled ui-state-disabled">
<label for="post">
სტატია
</label>
<textarea rows="15" cols="40" name="post" id="post" required="required"></textarea>
</div>
<div id="form-submit" class="field f_100 clearfix submit">
<input value="დამატება" type="submit" id="submit">
</div>
</form>
</div>

处理

if (isset($_POST['title'])) {$title = $_POST['title'];}
if (isset($_POST['post'])) {$post = $_POST['post'];}

<?php
if (isset($title) && isset($post))
{
/*can add post */
$insert = "INSERT INTO article ('title','post') VALUES ('$title','$post')";
$result = mysqli_query($connect,$insert);

if ($result == 'true') {echo "<p>post is added.</p>";}
else {echo "<p>post is not added.</p>";}
}
else
{
echo "<p>Fill all fields.</p>";
}
?>

处理后总是说没有添加帖子。检查数据库及其真实性。找不到错误。请帮忙。谢谢。

最佳答案

这是为您准备的声明。

$link = new MySQLi('localhost','username','password','database');

if(isset($_POST['title'],$_POST['post'])&& $_POST['title'] !="" && $_POST['post'] !=""){
$title = $_POST['title'];
$post = $_POST['post'];
if($query = $link->prepare('INSERT INTO article (title,post) VALUES(?,?)')){
$query->bind_param('ss',$title,$post);
$query->execute();
$query->close();
echo 'Success!';
}else{
echo 'Failure!';
}
}else{
echo 'You missed a field!';
}

关于php - $_POST 未插入数据库 - PHP MySQL,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28012253/

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