Python:错误处理递归函数错误

Question

这是我的第三个问题。由于堆栈溢出，我已经两次被选出该岛，所以我对发帖感觉有点不确定。

谁能告诉我下面的代码有什么问题。

所以我在错误中引用了一个函数。也就是说，如果发生错误，那么代码会重新引用它输入的函数再次运行。但是，当我第二次运行它时，我发现如果两个输入都是正确的(数字)输入，该函数不会返回值。

    #This is a program that is designed to calculate gross pay:

def main():
    payment = input2()
    print('Gross pay: $', format(payment, ',.2f'), sep='')

def input2():
    try:
        #we're first getting the number of hours that the user is working.

        hours = int(input("How manyu hours did you work?: "))

        pay_rate = int(input("Enter your hourly payrate here: "))

        #display the gross pay
        gross_pay = hours * pay_rate
        payment = gross_pay
        #display the gross pay:
    except ValueError:
        print('Error: Nope')
        input2()
        return payment

Answer 1

恕我直言，这不是递归的好用法，一个简单的 while 循环就可以了:

def input2():
    while True:
        try:
            #we're first getting the number of hours that the user is working.
            hours = int(input("How manyu hours did you work?: "))
            pay_rate = int(input("Enter your hourly payrate here: "))

            #display the gross pay
            gross_pay = hours * pay_rate
            return gross_pay
        except ValueError:
            print('Error: Nope')

修复你的递归调用看起来像:

def input2():
    try:
        #we're first getting the number of hours that the user is working. 
        hours = int(input("How manyu hours did you work?: "))
        pay_rate = int(input("Enter your hourly payrate here: "))

        #display the gross pay
        gross_pay = hours * pay_rate
    except ValueError:
        print('Error: Nope')
        gross_pay = input2()

    return gross_pay