php - 警告 : mysqli_query() [function. mysqli-query] : Empty query in C:\xampp\htdocs\tempahperalatan\page1. php on line 30 Error:

Question

嗨，我是 PHP 的初学者，谁能告诉我这里有什么问题？我似乎无法解决它。这是我的 PHP 编码:

<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "tempahperalatan";

// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}

if(isset($_POST['submit']))
{

    $pemohon = $_POST['namaPemohon'];
    $trkhMula = $_POST['tmula'];
    $trkhAkhir = $_POST['takhir'];
    $n_program = $_POST['namaProgram'];
    $lokasi = $_POST['lokasi'];
    $n_anjuran = $_POST['namaAnjuran'];
    $catatan = $_POST['catatan'];

$sql = "INSERT INTO daftartempah (pemohon, trkhMula, trkhAkhir, n_program, lokasi, n_anjuran, catatan) VALUES ('$namaPemohon', '$tmula', '$takhir', '$namaprogram', '$lokasi', '$namaAnjuran', '$catatan')";

}

if (mysqli_query($conn, $sql)) { //this is line 30
    echo "New record created successfully";
} else {
    echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}

mysqli_close($conn);
?>

和我的xampp有关系吗？提前谢谢你:)

Answer 1

把你的代码块

if (mysqli_query($conn, $sql)) { //this is line 30
    echo "New record created successfully";
} else {
    echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}

里面

if(isset($_POST['submit']))
{

就在 $sql = [...] 的下方

否则，如果您的表单未提交，脚本将尝试执行不存在的查询