python - 在有限的尝试游戏中猜猜我的号码

Question

作为我大学类(class)的一部分，我正在学习 python，我一直在尝试(重新)编写这个猜数字游戏，如果用户在 5 次尝试内未能正确猜出，该游戏将终止:

    # Guess My Number Mod 5 tries or bust


import random  

print("\nI'm thinking of a number between 1 and 100.")
print("Try to guess it in five tries or less")

my_number = random.randint(1, 100)
guess = int(input("Go on, Take a guess, I dare ya "))
tries = 1

while guess != my_number:
    if guess > my_number:
        print("Lower...")
    else:
        print("Higher...")
guess = int(input("Go on, Take a guess, I dare ya "))
tries += 1
if tries==5:
        input("You failed to guess the number was it that hard?\n Press any key to exit!)"

print("Well done you guessed correctly!The number was", my_number)
print("And it only took you", tries, "tries!\n")

input("\n\nPress the enter key to exit.")

我假设终止原因不起作用，因为我的 if 语句在 while 循环之外，我无法让它生效。

还有一些无效的语法，因为我累了，无法发现它。

如果可能的话，你们能给我一些提示，告诉我如何解决我想做的事情，因为我更有可能以这种方式学习。

Answer 1

您正在寻找 break 满足特定条件时退出循环。

if condition:
            # do something
            break # brings you out of the loop