android - 在android中检测互联网连接

Question

我在 android 中有一个应用程序，它是一种 TCP/IP 连接的客户端......这个应用程序使用从 GPS 提供商接收 GPSt 数据并将其发送到我的 TCP/IP 的服务器端IP 连接。

只是当没有互联网连接时，我必须将 GPS 数据存储在数据库中....一旦我再次连接到互联网，我必须重新启动客户端并重新连接到我的服务器并发送数据。

问题:1.如何在android中检测到互联网连接？(我的应用程序在模拟器上运行)

2.有没有可能，一旦我检测到互联网连接就要求我的线程客户端重新连接到服务器？？？

这是我的代码方案:

public void onCreate(Bundle savedInstanceState) {

    super.onCreate(savedInstanceState);

    setContentView(R.layout.client);

    lm = (LocationManager) getSystemService(Context.LOCATION_SERVICE);

    locationListener = new MyLocationListener();



    cThread = new Thread(new ClientThread(syncToken));

    cThread.start();

    lm.requestLocationUpdates(LocationManager.GPS_PROVIDER, 0, 0,
            locationListener);
}

---

public void onLocationChanged(Location loc) {
        if (loc != null) {

                    latitude = (int) (loc.getLatitude() * 1E6);

                    longitude = (int) (loc.getLongitude() * 1E6);


                    }
                }



            GeoPoint p = new GeoPoint(latitude, longitude);
            // geoPointsArray.add(p);
            db.insertData1(longitude, latitude);




        }

---

public class ClientThread implements Runnable {
    Object syncToken;



    public void run() {
        try {
            InetAddress serverAddr = InetAddress.getByName(serverIpAddress);

            socket = new Socket(serverAddr, 7001);

            Log.d(" ", "Clientul s-a conect");

        } catch (UnknownHostException e) {

            System.err.println("Don't know about host");

        } catch (IOException e) {

            System.err
                    .println("Couldn't get I/O for the connection to host");
        }

        try {

            os = new ObjectOutputStream(socket.getOutputStream());

        } catch (IOException e) {


            System.out.println(e);
        }

        while (true) {


            synchronized (syncToken) {

                try {
                    syncToken.wait();

                } catch (InterruptedException e) {

                    e.printStackTrace();

                }
            }

            if (socket != null && os != null) {

                    try {

            //send data through the socket

                    }catch (Exception e){

                        e.printStackTrace();

                    }

                    i++;

                }

            }


    }
}

---

编辑:

这是我做的:

private NetworkStateReceiver mNetSateReceiver = null;

private class NetworkStateReceiver extends BroadcastReceiver

{
    @Override

    public void onReceive( Context context, Intent intent )

    {
        ConnectivityManager connectivity = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);

        NetworkInfo info =connectivity.getActiveNetworkInfo();;

        if (info != null && info.isConnectedOrConnecting()) {


            System.out.println(" internet connection!");


        } 
        else
            System.out.println("no internet connection");



    }
}

---

onCreate(){



     registerReceiver( mNetSateReceiver, new IntentFilter(
                ConnectivityManager.CONNECTIVITY_ACTION ) );

        syncToken = new Object();

        cThread = new Thread(new ClientThread(syncToken));

        cThread.start();


}

---

 public void onDestroy(){ 

     super.onDestroy(); 

     db.close();

        unregisterReceiver( mNetSateReceiver );
 }

---

我知道每当我的状态连接改变时，我的 onReceive() 就会被调用....这意味着我应该在有互联网连接时在 onReceive() 中启动我的线程？？？？

如果你能为我澄清一点，我有点困惑......我应该从哪里开始你告诉我的 Intent？谢谢

Answer 1

这thread回答你的问题

关于启动时发生的事情。然后，您可以提出广播 Intent 并通过 Activity 接收 Intent ，一旦互联网可用，该 Activity 将执行更新

希望对你有帮助

编辑:通过广播 Intent ，我的意思是这样的。我不确定这是否是其他人可能提供的最佳解决方案...

如果检测到互联网，可以运行以下 Intent 广播。

广播 Intent 的代码:

  Intent i = new Intent(DO_REFRESH);
  sendBroadcast(i);

广泛接收 Intent :

doRefreshBroadcastReceiver drbr;
...

onResume() {
  // register the refreshing complete broadcast receiver
  IntentFilter intentFilter = new IntentFilter(DO_REFRESH);
  drbr = new doRefreshBroadcastReceiver();
  registerReceiver(drbr,intentFilter);        
}

    public class doRefreshBroadcastReceiver extends BroadcastReceiver { 

        @Override
        public void onReceive(Context context, Intent intent) {

            // call method to run fetch code...
        }
    }