python - AttributeError: 'RegexpReplacer' 对象没有属性 'replace'

Question

在定义类(RegexpReplacer)时，我发现了属性错误，但我没有得到这个问题的解决方案。下面给出了代码以及错误:

import re
replacement_patterns = [
(r'won\'t', 'will not'),
(r'can\'t', 'cannot'),
(r'i\'m', 'i am'),
(r'ain\'t', 'is not'),
(r'(\w+)\'ll', '\g<1> will'),
(r'(\w+)n\'t', '\g<1> not'),
(r'(\w+)\'ve', '\g<1> have'),
(r'(\w+)\'s', '\g<1> is'),
(r'(\w+)\'re', '\g<1> are'),
(r'(\w+)\'d', '\g<1> would')
]
class RegexpReplacer(object):
    def __init__(self, patterns=replacement_patterns):
        self.patterns = [(re.compile(regex), repl) for (regex, repl) in patterns]
        def replace(self, text):
                         s = text
                         for (pattern, repl) in self.patterns:
                             s = re.sub(pattern, repl, s)
                             return s
replacer=RegexpReplacer()
print(replacer.replace("can't is a contradicton"))

我发现了错误

Traceback (most recent call last):
 print(replacer.replace("can't is a contradicton"))
AttributeError: 'RegexpReplacer' object has no attribute 'replace'

请问有没有人可以帮忙

Answer 1

replace 方法隐藏在__init__ 中，您必须更正缩进:

import re
replacement_patterns = [
(r'won\'t', 'will not'),
(r'can\'t', 'cannot'),
(r'i\'m', 'i am'),
(r'ain\'t', 'is not'),
(r'(\w+)\'ll', '\g<1> will'),
(r'(\w+)n\'t', '\g<1> not'),
(r'(\w+)\'ve', '\g<1> have'),
(r'(\w+)\'s', '\g<1> is'),
(r'(\w+)\'re', '\g<1> are'),
(r'(\w+)\'d', '\g<1> would')
]
class RegexpReplacer(object):
    def __init__(self, patterns=replacement_patterns):
        self.patterns = [(re.compile(regex), repl) for (regex, repl) in patterns]
    def replace(self, text):
         s = text
         for (pattern, repl) in self.patterns:
             s = re.sub(pattern, repl, s)
         return s
replacer=RegexpReplacer()
print(replacer.replace("can't is a contradicton"))