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mysql - 我如何获得这三个 COUNTS() 的总和?

转载 作者:太空宇宙 更新时间:2023-11-03 11:13:37 24 4
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这是我的查询:

SELECT (SELECT COUNT(`id`) FROM `table1` WHERE `id` = '1') AS `count1`,
(SELECT COUNT(`id`) FROM `table2` WHERE `id` = '1') AS `count2`,
(SELECT COUNT(`id`) FROM `table3` WHERE `id` = '1') AS `count3`

如何得到 count1, count2, count3 的总和?

有什么方法可以在上面的查询中吗?

最佳答案

当然。只需将这些值加在一起:

SELECT (SELECT COUNT(`id`) FROM `table1` WHERE `id` = '1') +
(SELECT COUNT(`id`) FROM `table2` WHERE `id` = '1') +
(SELECT COUNT(`id`) FROM `table3` WHERE `id` = '1') AS `sum` ...

关于mysql - 我如何获得这三个 COUNTS() 的总和?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6837266/

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