mysql 从三个表中选择一个

Question

我有以下表格:

| table_one | table_two | table_three | table_four |
| t_one_id  | t_two_id  | t_three_id  | t_four_id  | // primary key (auto increment)
|           | two_nid   | three_nid   | four_nid   | // foreign key to table_one.t_one_id
| tone_date | ttwo_date | tthree_date | tfour_date | // time this was posted.
// other fields

和下面的查询，

SELECT `table_two` . * ,  `table_three` . * ,  `table_four` . * 
FROM  `table_two` 
JOIN ( `table_three` ) ON `table_three`.`three_nid`=1
JOIN ( `table_four`  ) ON  table_four`.`four_nid`=1
WHERE  `table_two`.`two_nid`=1

以及以下数据:

table_one: 1, 11/08/2011
table_two: 1, 1, 12/08/2011
table_three: 1, 1, 13/08/2011
table_four: 1, 1, 14/08/2011

现在我的查询一直返回零结果，尽管我希望它返回的是(在每个表的日期订购时):

result 1: 1 | 1 | 12/08/2011 | // this is from table_two
result 2: 1 | 1 | 13/08/2011 | // from table three
result 2: 1 | 1 | 14/08/2011 | // from four

我也试过以下但没有成功:

SELECT * FROM table_two t2, table_three t3, table_four t4 WHERE t2.two_nid = 1 OR t3.three_nid=1 OR t4.four_nid=1;

我的 SQL 查询哪里出错了？

提前致谢，如果需要更多信息，请随时询问。

Answer 1

如果要将每个表的结果显示为单独的行，则需要进行三个单独的选择，然后对结果进行 UNION。试试这个:

SELECT `table_two` . * 
FROM  `table_one` 
JOIN ( `table_two` ) ON `table_two`.`two_nid`=`table_one`.`t_one_id`
WHERE  `table_one`.`t_one_id`=1
UNION
SELECT `table_three` . * 
FROM  `table_one` 
JOIN ( `table_three` ) ON `table_three`.`three_nid`=`table_one`.`t_one_id`
WHERE  `table_one`.`t_one_id`=1
UNION
SELECT `table_four` . * 
FROM  `table_one` 
JOIN ( `table_four` ) ON `table_four`.`four_nid`=`table_one`.`t_one_id`
WHERE  `table_one`.`t_one_id`=1