来自创建表的 MySQL 错误 #1064

Question

我正在尝试创建一个数据库，我已经编写了代码，当我将它导入 phpMyAdmin 时，出现以下错误:

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'OPTION(OPTION_ID)
)' at line 7

和我写的代码:

CREATE DATABASE MAWARID;
USE MAWARID;

CREATE TABLE TOPIC (
    TOPIC_ID INT NOT NULL AUTO_INCREMENT,
    TOPIC_NAME VARCHAR(30) NOT NULL,

    PRIMARY KEY (TOPIC_ID)
);

CREATE TABLE QUESTION (
    QUESTION_ID INT NOT NULL AUTO_INCREMENT,
    QUESTION_NAME VARCHAR(100) NOT NULL,
    ANSWER INT NOT NULL,

    PRIMARY KEY (QUESTION_ID),
    FOREIGN KEY (ANSWER) REFERENCES OPTION(OPTION_ID)
);

CREATE TABLE OPTION (
    OPTION_ID INT NOT NULL AUTO_INCREMENT,
    OPTION_NAME VARCHAR(100) NOT NULL,
    QUESTION INT NOT NULL,

    PRIMARY KEY (OPTION_ID),
    FOREIGN KEY (QUESTION) REFERENCES QUESTION(QUESTION_ID)
);

我在这里检查了其他错误 #1064 问题，但似乎没有帮助我。

关于我为什么会收到此错误的任何想法？

Answer 1

您的脚本中存在循环依赖关系:QUESTION 引用 OPTION，反之亦然。

CREATE TABLE QUESTION (
    [...]
    FOREIGN KEY (ANSWER) REFERENCES OPTION(OPTION_ID)
);

CREATE TABLE OPTION (
    [...]
    FOREIGN KEY (QUESTION) REFERENCES QUESTION(QUESTION_ID)
);

要么删除它们(循环依赖通常是设计缺陷)，要么稍后在问题中尝试添加外键:

CREATE DATABASE MAWARID;
USE MAWARID;

CREATE TABLE TOPIC (
    TOPIC_ID INT NOT NULL AUTO_INCREMENT,
    TOPIC_NAME VARCHAR(30) NOT NULL,
    PRIMARY KEY (TOPIC_ID)
);

CREATE TABLE QUESTION (
    QUESTION_ID INT NOT NULL AUTO_INCREMENT,
    QUESTION_NAME VARCHAR(100) NOT NULL,
    ANSWER INT NOT NULL,
    PRIMARY KEY (QUESTION_ID)
    -- no foreign key creation here
);

CREATE TABLE `OPTION` (
    OPTION_ID INT NOT NULL AUTO_INCREMENT,
    OPTION_NAME VARCHAR(100) NOT NULL,
    QUESTION INT NOT NULL,

    PRIMARY KEY (OPTION_ID),
    FOREIGN KEY (QUESTION) REFERENCES QUESTION(QUESTION_ID)
);

-- create your foreign key here
ALTER TABLE QUESTION ADD FOREIGN KEY (ANSWER) REFERENCES `OPTION`(OPTION_ID);

另外，OPTION是保留字，最好用backtips括起来或者另起一个名字。