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php - AsyncTask Android 中的 Http 请求

转载 作者:太空宇宙 更新时间:2023-11-03 10:56:34 26 4
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我正在尝试制作一个应用程序,该应用程序在应用程序中获取用户名和密码,并使用 http 请求将它们发送到 mysql 数据库,在检查数据库中是否存在用户后,我看到 TextView 中显示的文本说应用程序“正确的用户名和密码”,如果它不存在,我会看到显示的文本“不正确的用户名或密码”我既看不到正确也看不到错误点击按钮登录后我什么也看不到

Logindb 类

    public class Logindb extends Activity {
Button login;
EditText u, p;
TextView res;

@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.logindb);

login = (Button) findViewById(R.id.login);
u = (EditText) findViewById(R.id.u);
p = (EditText) findViewById(R.id.p);
res = (TextView) findViewById(R.id.res);
login.setOnClickListener(new View.OnClickListener() {

@Override
public void onClick(View v) {
new MyAsyncTask().execute(u.getText().toString(), p.getText()
.toString());
}
});
}

private class MyAsyncTask extends AsyncTask<String, Integer, Double> {
@Override
protected Double doInBackground(String... params) {
postData(params[0], params[1]);
return null;
}

protected void onPostExecute(Double result) {
Toast.makeText(getApplicationContext(), "command sent",
Toast.LENGTH_LONG).show();
}

protected void onProgressUpdate(Integer... progress) {}

public void postData(String a, String b) {
ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>();
postParameters.add(new BasicNameValuePair("username", a));
postParameters.add(new BasicNameValuePair("password", b));

String response = null;
try {
response = CustomHttpClient.executeHttpPost(
"http://192.168.1.11/new/check.php", postParameters);
String result = response.toString();
result = result.replaceAll("\\s+", "");
if (!result.equals("0")) {
res.setText("A Correct Username and Password");
}
else
res.setText("Incorrect Username or Password");
} catch (Exception e) {
res.setText(e.toString());
}
}
}

@Override
public boolean onCreateOptionsMenu(Menu menu) {
getMenuInflater().inflate(R.menu.logindb, menu);
return true;
}
}

PHP 文件 check.php

     <?php
$un=$_POST['username'];
$pw=$_POST['password'];
//connect to the db

$host="localhost"; // Host name
$user="root"; // Mysql username
$pswd="123"; // Mysql password
$db="pet_home"; // Database name
$tbl_name="users"; // Table name

$conn = mysql_connect($host, $user, $pswd);
mysql_select_db($db, $conn);
//run the query to search for the username and password the match
$query = "SELECT * FROM $tbl_name WHERE first_name = '$un' AND password = '$pw'";

$result = mysql_query($query) or die("Unable to verify user because : ".mysql_error());
//this is where the actual verification happens
if(mysql_num_rows($result) > 0)
echo mysql_result($result,0); // for correct login response
else
echo 0; // for incorrect login response
?>

logindb.xml`

     <EditText
android:id="@+id/u"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_alignParentTop="true"
android:layout_centerHorizontal="true"
android:layout_marginTop="56dp"
android:ems="10" />

<EditText
android:id="@+id/p"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_alignLeft="@+id/u"
android:layout_below="@+id/u"
android:layout_marginTop="22dp"
android:ems="10"
android:inputType="textPassword" />

<Button
android:id="@+id/login"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_below="@+id/p"
android:layout_centerHorizontal="true"
android:layout_marginTop="67dp"
android:text="Login" />

<TextView
android:id="@+id/res"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_alignLeft="@+id/login"
android:layout_below="@+id/p"
android:layout_marginTop="27dp"
android:text="OK"
android:textAppearance="?android:attr/textAppearanceSmall"
android:textColor="@android:color/black" />

</RelativeLayout>`

最佳答案

它不起作用,因为您正在修改 doInBackground 中的 TextView。您所有的视觉修改都必须在您的 onPostExecute 中调用所以这里你需要做的是从 postData 返回字符串结果,并在你的 onPostExecute 中移动以下代码:

  if (!result.equals("0")) {
// Intent in = new Intent(Logindb.this, Welcome.class);
// LoadPreferences();
res.setText("A Correct Username and Password");
//startActivity(in);
}
else
res.setText("Incorrect Username or Password");

关于php - AsyncTask Android 中的 Http 请求,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20146417/

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