php - 在一个 PHP 文件中运行 2 个 MySQL 更新查询

Question

我试着跑

// Create connection
$conn = new mysqli($servername,$username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
} 
$sql = "UPDATE pm_videos SET `description` = REPLACE(  `description` ,'Facebook',  '')";
$sql = "UPDATE pm_videos SET `description` = REPLACE(  `description` ,'Twitter',  '')";

if ($conn->query($sql) === TRUE) {
echo "Record updated successfully";
} else {
echo "Error updating record: " .  $conn->error;
}
$conn->close();

但只有推特会被取代。我是 PHP 的新手。也许有人可以帮我解决这个问题。谢谢。

Answer 1

$conn->query($sql) 语句运行您的查询。在运行它之前，您正在覆盖第一个 $sql(Facebook 的那个)。你会想做类似的事情

$sql = "UPDATE pm_videos SET `description` = REPLACE(  `description` ,'Facebook',  '')";
if ($conn->query($sql) === TRUE) {
    echo "Record updated successfully with Facebook";
} else {
    echo "Error updating record: " .  $conn->error;
}
$sql = "UPDATE pm_videos SET `description` = REPLACE(  `description` ,'Twitter',  '')";
if ($conn->query($sql) === TRUE) {
    echo "Record updated successfully with Twitter";
} else {
    echo "Error updating record: " .  $conn->error;
}