c# - 自动映射器、复杂属性和继承

Question

我正在尝试让 AutoMapper 正常工作，但我真的坚持执行一项简单的任务。我在用户实体中定义了一个复杂类型:

[ComplexType]
public class CustomerProfile
{
    public string       FirstName                { get; set; }
    public string       LastName                 { get; set; }
    // ...
}

public class User
{
    public long Id {get; set;}
    public string Email { get; get; }
    public CustomerProfile CustomerProfile { get; set; }
}

我有这样的 View 模型:

public class CustomerViewModel : CustomerProfile
{
    public string Email { get; set; }
}

所以我只有 View 模型中的所有 CustomerProfile 属性以及电子邮件。

我想将 User 映射到 CustomerViewModel。我尝试了一切但实际上没有成功。即使这段代码也不起作用:

Mapper.CreateMap<CustomerProfile, CustomerViewModel>();

Automapper 只是拒绝映射任何东西。

如何映射？谢谢。

Answer 1

您可以使用 .ConstructUsing 从 User 实例创建一个 CustomerViewModel。然后，只要名称匹配，其余属性(例如，Email)将由 AutoMapper 自动映射:

Mapper.CreateMap<CustomerProfile, CustomerViewModel>();

Mapper.CreateMap<User, CustomerViewModel>()
    .ConstructUsing(src => Mapper.Map<CustomerViewModel>(src.CustomerProfile));

示例: https://dotnetfiddle.net/RzpD4z

---

更新

要使 AssertConfigurationIsValid() 通过，您需要忽略手动映射的属性。您还需要从 CustomerProfile → CustomerViewModel 映射中忽略 CustomerViewModel 上的 Email 属性，因为这将被采用由 User 处理 → CustomerViewModel 映射:

Mapper.CreateMap<CustomerProfile, CustomerViewModel>()
    // Ignore Email since it's mapped by the User to CustomerViewModel mapping.
    .ForMember(dest => dest.Email, opt => opt.Ignore());

Mapper.CreateMap<User, CustomerViewModel>()
    .ConstructUsing(src => Mapper.Map<CustomerViewModel>(src.CustomerProfile))
    // Ignore FirstName/LastName since they're mapped above using ConstructUsing.
    .ForMember(dest => dest.FirstName, opt => opt.Ignore())
    .ForMember(dest => dest.LastName, opt => opt.Ignore());

更新示例: https://dotnetfiddle.net/KitDiC