java - Android 中的 Saxparser 异常

Question

我正在从这个 XML url 解析数据文本输入因用户而异。每当文本变量中有空格时，我都会收到此异常:

 org.apache.harmony.xml.ExpatParser$ParseException: At line 11, column 2: mismatched tag
 org.apache.harmony.xml.ExpatParser.parseFragment(ExpatParser.java:520)
 org.apache.harmony.xml.ExpatParser.parseDocument(ExpatParser.java:479)
 org.apache.harmony.xml.ExpatReader.parse(ExpatReader.java:318)
 org.apache.harmony.xml.ExpatReader.parse(ExpatReader.java:275)
 gps.app.tkartor.XMLObjects.XMLParser.findStreet(XMLParser.java:99)

如果没有空格，它工作正常。解析代码:

public void findStreet(String searchWord) {
    try {
        url = new URL(
                "http://maps.travelsouthyorkshire.com/iGNMSearchService.asmx/TextSearch?text="
                        + searchWord + "&maxResults=100");
        System.out.println(url.toString());
        parserFactory = SAXParserFactory.newInstance();
        parser = parserFactory.newSAXParser();
        reader = parser.getXMLReader();
        streetHandler = new StreetHandler();
        reader.setContentHandler(streetHandler);
        reader.parse(new InputSource(url.openStream()));//line 99
        poi = streetHandler.getAllStreets();

    } catch (Exception e) {
        e.printStackTrace();
    }
}

Answer 1

用'+'表示空格

http://maps.travelsouthyorkshire.com/iGNMSearchService.asmx/TextSearch?text=West+bar&maxResults=100

因此，在您的情况下，您必须替换字符串“searchWord”的空格。有点像

 searchWord = searchWord.replace(" ", "+");