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c++ - 类的析构函数中的访问冲突读取位置

转载 作者:太空宇宙 更新时间:2023-11-03 10:22:28 25 4
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我已经构建了 Graph 类、一个构造函数和一个析构函数。我的问题是:当我编译这段代码时,我在 delete [] mat[i]; 这行出错,错误是“访问冲突读取位置 0xDDDDDDCD”。而且我不确定我做错了什么。我的意思是我只删除动态分配的内存。稍后编辑:即使我使用这个而不是我的方法:

Graph(int nr_noduri) {


this->nr_noduri = nr_noduri;
mat = new bool* [nr_noduri];
for (int i = 0; i < nr_noduri; i++) {
mat[i] = new bool[nr_noduri];
}
for (int i = 0; i < nr_noduri; i++) {
for (int j = 0; j < nr_noduri; j++) {
mat[i][j] = 0;
}
}
}

我的代码是:

 #include <iostream>
#include <cstdlib>
using namespace std;

class Graph {
bool** mat;
int nr_noduri;

public:
Graph(int nr_noduri) {
this->nr_noduri = nr_noduri;
mat = (bool**)calloc(nr_noduri, sizeof(bool*));
for (int i = 0; i < nr_noduri; i++) {
mat[i] = (bool*)calloc(nr_noduri, sizeof(bool));
}
}

int size() {
return nr_noduri;
}

void addArc(int v, int w) {
if (v < nr_noduri && w < nr_noduri) {
mat[v][w] = true;
}
else cout << "Not enough nodes !" << endl;
}

bool isArc(int v, int w) {
return (mat[v][w] == true);

}

void print() {
for (int i = 0; i < nr_noduri; i++) {
cout << endl;
for (int j = 0; j < nr_noduri; j++) {
cout << mat[i][j] << " ";
}
}
cout << endl;
}

~Graph() {
//cout << nr_noduri;
for (int i = 0; i < nr_noduri; i++) {
delete [] mat[i];
}
delete[] mat;
}

friend void dfs(Graph g, int v, bool vazut[]);
};

void dfs(Graph g, int v, bool vazut[]) {
int w;
vazut[v] = true;
for (w = 0; w < g.size(); w++) {
if (g.isArc(v, w) && !vazut[w]) {
cout << v << "->" << w;
dfs(g, w, vazut);
}
}
}


int main() {
int nr_noduri;
cin >> nr_noduri;
Graph v(nr_noduri);
v.print();
v.addArc(1, 2);
v.addArc(2, 5);
cout << v.isArc(1, 2) << endl;
v.print();
bool vazut[100];
dfs(v, 1, vazut);
return 0;
}

最佳答案

您不能使用 delete释放由 calloc 分配的内存(或任何 malloc 函数族)。使用 new而不是分配内存。

Graph(int nr_noduri) {
this->nr_noduri = nr_noduri;
mat = new bool*[nr_noduri];
for (int i = 0; i < nr_noduri; i++) {
mat[i] = new bool[nr_noduri];
}
}

更好的是,使用 std::vector<std::vector<bool>>保存数据。

class Graph {
std::vector<std::vector<bool>> mat;

Graph(int nr_noduri) : mat(nr_noduri, std::vector<bool>(nr_noduri) {}

...
};

关于c++ - 类的析构函数中的访问冲突读取位置,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58629872/

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