c++ - 运算符重载

Question

我对有关运算符重载的话题感到困惑。见以下代码:

#include <iostream>;

class Vectors {
public:
    int x, y;
    Vectors() {};
    Vectors(int a,int b) {
        x = a, y = b;
    }
    Vectors operator+(Vectors aso) {
        Vectors brandNew;
        std::cout << "ASO X " << aso.x << std::endl;
        std::cout << "ASO Y " << aso.y << std::endl;
        brandNew.x = brandNew.x + aso.x;
        brandNew.y = brandNew.y + aso.y;
        return (brandNew);
    };
};
int main() {
    Vectors v1(2,3);
    Vectors v2(4,5);
    Vectors v3;
    v3 = v1 + v2;

    std::cout << "Vector V3 X : " << v3.x << std::endl;
    std::cout << "VECTOR V3 Y : " << v3.y << std::endl;
}

当我打印 aso.x 时，y 给了我 4 和 5。我想做的是同时添加 v1 和 v2；表示 v1 和 v2 的 x，以及 v1 和 v2 的 y。然后，将其传递给 Vectors 对象并返回该对象。

鉴于我已具备以上条件，我该如何实现？

Answer 1

你可能是说

Vectors operator+(const Vectors& aso) {
        Vectors brandNew;
        std::cout << "ASO X " << aso.x << std::endl;
        std::cout << "ASO Y " << aso.y << std::endl;
        brandNew.x = x + aso.x;
        brandNew.y = y + aso.y;
        return (brandNew);
    };

或

Vectors operator+(const Vectors& aso) {
    Vectors brandNew(x + aso.x, y + aso.y);
    std::cout << "ASO X " << aso.x << std::endl;
    std::cout << "ASO Y " << aso.y << std::endl;
    return (brandNew);
};

---

根据您的评论

But about if there were three.

像这样链接运算符

int main() {
    Vectors v1(2,3);
    Vectors v2(4,5);
    Vectors v3(7,11);
    Vectors v4;
    v4 = v1 + v2 + v3;

    std::cout << "Vector V4 X : " << v4.x << std::endl;
    std::cout << "Vector V4 X : " << v4.y << std::endl;
}

参见 Live Demo