c++ - 在大型项目中按名称查找函数的最佳方法是什么？

Question

假设我们有一个包含 100 个文件的项目(例如一个库)，每个文件包含大约 1000 行代码。你想找到函数 awesome_foo(...)你怎么做呢？老实说，我发现 grepping 它令人毛骨悚然且无效......

编辑:我主要寻找函数定义

Answer 1

grep -irnw "awesome_foo"* 肯定会给你结果。

参数是:

-i, --ignore-case

Ignore case distinctions in both the PATTERN and the input files.

-n, --line-number

Prefix each line of output with the line number within its input file.

-R, -r, --recursive

Read all files under each directory, recursively; this is equivalent to the -d recurse option.

-w, --word-regexp

Select only those lines containing matches that form whole words. The test is that the matching substring must either be at the beginning of the line, or preceded by a non-word con- stituent character. Similarly, it must be either at the end of the line or followed by a non-word constituent character. Word- constituent characters are letters, digits, and the underscore.