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c++ - boost::multi_index_container 中的部分字符串搜索

转载 作者:塔克拉玛干 更新时间:2023-11-03 08:03:44 27 4
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我有一个结构来存储有关人员的信息和 multi_index_contaider 来存储此类对象。多索引用于按不同条件进行搜索。

我已将几个人添加到容器中,并希望按姓氏查找人员。如果我使用整个姓氏,效果很好。但是,如果我尝试通过姓氏的一部分(姓氏的第一个字母)查找人,它不会返回任何结果。

如您所知,部分字符串搜索对 std::set<string 很有用。 >。所以我只用结构包装字符串并失去了该功能。

这是可编译的代码:

#include <iostream>
#include <string>
#include <algorithm>
#include <set>

#include <boost/multi_index_container.hpp>
#include <boost/multi_index/ordered_index.hpp>
#include <boost/multi_index/identity.hpp>
#include <boost/multi_index/member.hpp>
#include <boost/multi_index/composite_key.hpp>

#define DEFAULT_ADDRESS "Moscow"
#define DEFAULT_PHONE "11223344"

typedef unsigned int uint;

using namespace boost;
using namespace boost::multi_index;

struct person
{
std::string m_first_name;
std::string m_last_name;
std::string m_third_name;
std::string m_address;
std::string m_phone;

person();
person(std::string f, std::string l, std::string t = "", std::string a = DEFAULT_ADDRESS, std::string p = DEFAULT_PHONE) :
m_first_name(f), m_last_name(l), m_third_name(t), m_address(a),
m_phone(p) { }

virtual ~person()
{ /*std::cout << "Destructing person..." << std::endl;*/ }

person& operator=(const person& rhs);
};

typedef multi_index_container<
person,
indexed_by<
ordered_unique<identity<person> >,
ordered_non_unique<
composite_key<
person,
member<person, std::string, &person::m_last_name>,
member<person, std::string, &person::m_first_name>,
member<person, std::string, &person::m_third_name>
>
>
>
> persons_set;

person& person::operator=(const person &rhs)
{
m_first_name = rhs.m_first_name;
m_last_name = rhs.m_last_name;
m_third_name = rhs.m_third_name;
m_address = rhs.m_address;
m_phone = rhs.m_phone;
return *this;
}

bool operator<(const person &lhs, const person &rhs)
{
if(lhs.m_last_name == rhs.m_last_name)
{
if(lhs.m_first_name == rhs.m_first_name)
return (lhs.m_third_name < rhs.m_third_name);

return (lhs.m_first_name < rhs.m_first_name);
}
return (lhs.m_last_name < rhs.m_last_name);
}

std::ostream& operator<<(std::ostream &s, const person &rhs)
{
s << "Person's last name: " << rhs.m_last_name << std::endl;
s << "Person's name: " << rhs.m_first_name << std::endl;
if (!rhs.m_third_name.empty())
s << "Person's third name: " << rhs.m_third_name << std::endl;
s << "Phone: " << rhs.m_phone << std::endl;
s << "Address: " << rhs.m_address << std::endl << std::endl;
return s;
}

struct comp_persons
{
bool operator()( const person& p1, const person& p2) const
{
if (p2.m_last_name.empty()) return false;
return ( p1.m_last_name.find(p2.m_last_name) == 0 );
}
};



int main()
{
persons_set my_set;

persons_set::nth_index<0>::type &general_index = my_set.get<0>(); // shortcut to the 1st index
persons_set::nth_index<1>::type &names_index = my_set.get<1>(); // shortcut to the 2nd index

// adding persons
general_index.insert(person("Alex", "Johnson", "Somename"));
general_index.insert(person("Alex", "Goodspeed"));
general_index.insert(person("Peter", "Goodspeed"));
general_index.insert(person("Akira", "Kurosava"));

// search via 2nd index (based on last_name)
std::pair<persons_set::nth_index<1>::type::const_iterator, persons_set::nth_index<1>::type::const_iterator>
n_it = names_index.equal_range("Goodspeed");

// this finds nothing
/*std::pair<persons_set::nth_index<1>::type::const_iterator, persons_set::nth_index<1>::type::const_iterator>
n_it = names_index.equal_range("Goodspe");*/

// idea by Kirill V. Lyadvinsky. This code crashes on the start.
// I guess because behaviour of comp_persons differs from default less<> or reloaded operator <
/*std::pair<persons_set::nth_index<1>::type::const_iterator, persons_set::nth_index<1>::type::const_iterator>
n_it = std::equal_range(names_index.begin(), names_index.end(), person("Alex", "Goodspe"), comp_persons());*/

std::copy( n_it.first ,n_it.second,
std::ostream_iterator<person>(std::cout));

return 0;

}

最佳答案

您可以将 equal_rangelower_bound 与自定义比较仿函数一起使用。它可能如下所示(未经测试):

struct comp_substr {
bool operator()( const char* input, const std::string& s) const {
if ( s.empty() ) return false;
return ( s.find( input ) == 0 );
}

// ...
// use it as follows
n_it = names_index.equal_range( "Good", comp_substr() );

关于c++ - boost::multi_index_container 中的部分字符串搜索,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/3000603/

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