c++ - 如何从多索引中获取值

Question

我正在尝试使用 boost-multi 索引做一个多映射(4 个变量)。我能知道如何获取特定索引的值吗？

tmp_Container.get<name>().find("aaa")->firstVariable

编辑

struct EnumStruct
{
    int microsoftEnum;
    std::string microsoftEnumString;
    int localEnum;
    std::string localEnumString;
}

typedef bmi::multi_index_container<
    EnumStruct,
    bmi::ordered_unique<bmi::tag<localEnum>,bmi::member < 
        EnumStruct,std::string,&EnumStruct::localEnumString > >
    >
> boost_Enum_Container;

boost_Enum_Container enumStructContainer;


int main()
{
    enumStructContainer.insert(EnumStruct(1,"MS_1",11,"LOC11"));
    enumStructContainer.insert(EnumStruct(2,"MS_2",22,"LOC22"));
    enumStructContainer.insert(EnumStruct(3,"MS_3",33,"LOC33"));
    //enumStructContainer.get<0>().find(1);
    //boost_Enum_Container::index<localEnum>::type&
    localEnum_Index=enumStructContainer.get<localEnum>().find(22)->firstVariable;
    boost_Enum_Container::iterator
    return 0;
}

Answer 1

您需要 project功能。参见 http://www.boost.org/doc/libs/1_39_0/libs/multi_index/doc/tutorial/basics.html#projection和 http://www.boost.org/doc/libs/1_46_0/libs/multi_index/doc/reference/multi_index_container.html#projection .因此:tmp_Container.project<0>(tmp_Container.get<name>.find("aaa")) .