带有类错误消息的 C++ 温度计

Question

我知道温度计的问题已经解决了，但我想我会试一试。

我不断收到错误消息“使用未声明的标识符‘converterc’”和“使用未声明的标识符‘converterf’”。有什么想法吗？

秒杀

 #include <iostream>
#include "converters.h"
using namespace std;

int main()
{
    int degree;
    int weehoo;

    cout<<"\n\n\n\t\t Enter the temperature : ";
    cin>>degree;
    cout<<"\n\n\t\t If the temperature is in Celsius enter 0, if Farenheit enter 1 :";
    cin>>weehoo;

    if (weehoo==0)
    {
        cout<<"\n\n\t\tThe temperature in Farenheit is "<<converterc(degree,weehoo)<<endl;
    }
    else
    {
        cout<<"\n\n\t\tThe temperature in Celsius is "<<converterf(degree,weehoo)<<endl;
    }
    return 0;
}
#ifndef __again_converters_h
#define __again_converters_h
#endif
#pragma once

class Thermometer
{
private:
float degreeC;   //celcius
float degreeF;   //farenheit

public:
void setCelcius (float c) {degreeC=c;}
void setFarenheit (float f) {degreeF=f;}
float getCelcius (void){return degreeC;}
float getFarenheit (void){return degreeF;}
Thermometer  (float degree=0,float f=0, float c=0,float outtemp=0);
float converterc(int degree,int weehoo);
float converterf(int degree,int weehoo);
};

转换器.cpp 文件 #include "converters.h"

 float Thermometer::converterf(int degree,int weehoo)
{
degreeC=((degree-32) * (.5556));
return degreeC ;

}
float Thermometer::converterc(int degree,int weehoo)
{
degreeF=((1.8)*degree)+32;
return degreeF;
}

Answer 1

converterc 和 converterf 是类 Thermometer 的成员函数，但您在没有 Thermometer 的情况下调用它们实例。

如何在您的 main 中创建一个 Thermometer 实例？

Thermometer tm;
tm.converterc(degree, weehoo);